Answer:
p value from chi square = 0.081
Step-by-step explanation:
Given that sociologists say the percentage of the classic music lovers is about 5%. From the survey, we know that only 83 out of 2000 people listen to the classic music. Let denote the proportion of the classic music lovers. The hypotheses are H0: p=0.05 vs Ha: p≠0.05
p value = 0.09
Instead of this if we do chi square
H0: Proportion of music lovers is 5% and non music lovers is 95%
Ha: Proportions are not as per the estimate
(Two tailed chi square test)
Observed 83 1917 2000
Expected 100 1900 2000
O-E -17 17 0
chi square
(O-E)^2/E 2.89 0.1521 3.0421
df =1
p value from chi square = 0.081
Though p value is not exactly the same, the conclusion in both tests are the same
JM=12
JL= 14
MN=?
MK=?
VT= 11
UV= 9
RS=?
ST=?
GF=23
HF=20
GH=?
GE=?
M<1=?
M<2=?
M<3=?
M<4=?
M<5=?
M<6=?
M<7=?
M<8 = 90 degrees
WXZ = 34 degrees
WVZ=90 degrees
ZYW= 56 degrees
These are the only answers I knew, I’m sorry I couldn’t find the rest. If I do find more answers, I’ll comment them.
Answer:
The range of the Morning box plot is the same as the range of the Afternoon box plot.
Step-by-step explanation:
Data provided in the question
Number line = 0 to 16
Morning whiskers range = 3 to 15
Box range = 5 to 12
Line divided = 8
Afternoon whiskers range = 4 to 16
Box range = 8 to 15
Line divided = 14
Based on the above information,
The morning whiskers range difference is
= 12 - 5
= 7
And, the afternoon whiskers range difference is
= 15 - 8
= 7
Therefore the first option is correct
Answer:
$560
Step-by-step explanation:
Given that :
Principal, P= $500
Interest rate, r = 12% per year
Amount in account after 1 year
Time = 1 year
Using the relation :
A = P(1 + rt)
A = final amount in account
A = $500(1 + 0.12(1))
A = $500(1 + 0.12)
A = $500(1.12)
A = $560
B)16
add the two equations and equal it to 90 and solve to get 16
