F -6*-6 = 36 which is a positive interger
Hello there! The area of the triangle portion is 11 square units, the area of the rectangle portion is 77 square units, and the area of the entire figure is 88 square units.
To find the area of the triangle, we can follow the formula:
A = LW/2 (which means length x width divided by 2)
Given the formula:
2 • 11 = 22
22 divided by 2 gives us 11 square units.
To find the area of the rectangle portion, we can follow the area formula:
A = LW (which means area = length x width)
Given the formula:
7 • 11 = 77 square units
To find the area of the whole figure, we add the areas of both isolated shapes:
11 + 77 = 88 square units.
Therefore, our area for the entire figure is 88 square units. If you need any extra help, let me know and I will gladly assist you.
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
The graph of g(x) = f(x) + 5 will have the graph of f(x) moved 5 units upward. The best choice is the last one.
_____
Adding 5 to each y-value (the output of f(x)) moves it upward by 5 units.
(1, 2.50)
(2, 4.50)
(5, 10.50)
(8, 16.50)
Domain is : 1, 2, 5, 8
Range is : 2.50, 4.50, 10.50, 16.50