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barxatty [35]
3 years ago
7

What is 6/4 simplified

Mathematics
2 answers:
Rashid [163]3 years ago
6 0
Since this is an improper fraction, you simplify it into a mixed number. 
4 goes into 6 1 time. 2 left left over, resulting in 1 2/4. Simplify that into 
1 1/2
SVEN [57.7K]3 years ago
6 0
3/2
because you can divide both 6 and 4 by 2 and you get the answer of 3/2

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A/b=2/5 and b/c=3/8 find a/c​
m_a_m_a [10]

Answer:

\frac{a}{c} = \frac{3}{20}

Step-by-step explanation:

\frac{a}{c} = \frac{a}{b} × \frac{b}{c} = \frac{2}{5} × \frac{3}{8} = \frac{6}{40} = \frac{3}{20}

3 0
3 years ago
I needs help please and tank chu
PIT_PIT [208]

9514 1404 393

Answer:

  C  {2, 4, 9, 16}

Step-by-step explanation:

The domain is the list of numbers at the tails of the arrows.

The range is the list of numbers at the heads of the arrows: {2, 4, 9, 16}.

5 0
3 years ago
Company A is offering $6,000 for the first month's salary and will increase the amount each month by $5,000. Company B is offeri
Alex17521 [72]

The month in which Company B's payment will first exceed Company A's payment is C) Month 7.

Step-by-step explanation:

Step 1:

Company A offers $6,000 for the first month and increases the salary each month by $5,000.

Company B offers $700 for the first month but doubles the payments each month.

We need to determine which month company B's payment is greater than company A's payment.

Step 2:

According to the table, at month 6 company A pays $31,000 while company B pays $22,400.

However after this month, in the seventh-month company A pays $36,000 while company B pays $44,800, which is higher than company A's salary.

So The month in which Company B's payment will first exceed Company A's payment is C) Month 7.

4 0
3 years ago
PLEASE HELP :(!!!!!!!!
Levart [38]

Answer:

19/3 > square root of 37 > 6.08171 > 6.012

4 0
3 years ago
Find the sum of each set of numbers, as well as the size n of each set of numbers (n = number of numbers in the set). Use these
guapka [62]

We have to add numbers without a calculator.

1) 25, 35, 19, 31

We can group them by the last digit, so they are easy to add:

25 + 35 = 20 + 30 + 5 +5 = 50 + 10 = 60

19 + 31 = 10 + 30 + 9 +1 = 40 + 10 = 50

Then, 60 + 50 = 110

numbers in the set n = 4

Sum = 110

2) 101, 73, 49, 27, 24, 36

We can group them again by the last digit (adding 10, like the previous example).

We can substract the last digit from one number and add it to the other one. The result will be the same, but they will become easier to add.

101 + 49 = 100+50 = 150

73 + 27 = 70 + 30 = 100

24 + 36 = 20 + 40 = 60

150 + 100 + 60 = 250 + 60 = 310

numbers in the set n = 6

Sum = 310

3) 25, 25, 25, 30, 30, 30, 32, 32, 32

In this case we have 3 times the same numbers, so we can add the three different numbers and then multiply the total by 3.

We can use the properties of the multiplication to simplify the product (we will use the distributive property)

25 + 30 + 32 = 27 + 30 + 30 = 87

87 * 3 = 80*3 + 7*3 = 240 + 21 = 261

numbers in the set n = 9

Sum = 261

8 0
1 year ago
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