<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
Answer:
2
Step-by-step explanation:
it's literally 6-4 = 2
The answer
let p' be the corresponding angle of the angle p (that is because of the prallelism and the transversal, look the image)
but p' and p are correspondant angles implies p'=p,
looking at the figure, p' and q are opposite angles
so q=p' and p'=p implies q=p
the answer is
<span>p = q</span>
<h2>189 boys is 54%</h2><h2>x is 46%(100-54)</h2><h2>Cross multiply:</h2><h2>189*46%=54%*x</h2><h2>86.94=0.54x</h2><h2>x=161</h2><h2>189 boys 161 girls</h2><h2>350 altogether</h2><h2>Hope this helps plz hit the crown :D</h2>
Answer:
Maya painted 3/4 of her art project in the morning and 1/8 of her project in the evening which equation can Maya use c to find how much of the project she painted dtrdtrdtrdtrdrt9945 is waiting for your help.
Step-by-step explanation: