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steposvetlana [31]

2 years ago

6

Find the perimeter of the triangle

2 answers:

BARSIC [14]2 years ago

5 0

I think the answer is 29.
Good luck in your math homework:)

vredina [299]2 years ago

4 0

We can find the area of the big triangle, and subtract it from the small 4 x 2 triangle.

bh/2
3*8/2
12

bh/2
2*4/4
4

12 - 8
4 unit²

To find the perimeter:
a² + b² = c²
9 + 64 = c²
73 = c²
√73 = c

√73 + 3 + 8 + 2 + 4
√73 + 17

Hope this helps!

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Goshia [24]

<t =33 since triangle RUT is isosceles (RU = TU)

<r + <u + <t = 180 triangle = 180

33 + <u + 33 = 180

66 + <u = 180

< u =114

<rus = < sut from the diagram

<rus + <sut = <u

x + x = 114

2x = 114

divide by 2

x = 57

6 0

3 years ago

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vladimir2022 [97]

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Step-by-step explanation:

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3 years ago

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saul85 [17]

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What are the rigid transformations that will map AABC to ADEF?

asambeis [7]

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6 0

3 years ago

Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$

but we will find sample size "n"

$\sqrt{n} = \frac{z_{a} S.D}{maximum error}$

Squaring on both sides , we get

$n = (\frac{z_{a} S.D}{maximum error})^2$

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

$n = (\frac{z_{a} p(1-p)}{maximum error})^2$

n≤ $(\frac{2.56X\frac{1}{2} }{0.02}) ^{2}$ ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is n = 4225

<u>verification</u>:-

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$ = $\frac{2.56 1/2}{\ \sqrt{4225} }$ = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0

3 years ago