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3 years ago

11

What is greater .584 or.58?

1 answer:

AURORKA [14]3 years ago

8 0

.584
.58 is equal to .580, like how 1 = 1.0

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Operations with Radical Expressions

lisov135 [29]

Answer: $30\sqrt{11}$

<u>Step-by-step explanation:</u>

$3\sqrt{50} * \sqrt{22}$

= $3\sqrt{5*5*2} * \sqrt{2*11}$

= $3\sqrt{5*5*2*2*11}$

= $3*5*2\sqrt{11}$

= $30\sqrt{11}$

******************************************

Answer: $6\sqrt{30}$

<u>Step-by-step explanation:</u>

$\sqrt{20} * \sqrt{3} * \sqrt{18}$

= $\sqrt{2*2*5} * \sqrt{3} * \sqrt{3*3*2}$

= $\sqrt{2*2*5*3*3*3*2}$

= $2*3\sqrt{5*3*2}$

= $6\sqrt{30}$

********************************************

Answer: $-\sqrt{5}$

<u>Step-by-step explanation:</u>

$4\sqrt{20} - 3\sqrt{45}$

= $4\sqrt{2*2*5} - 3\sqrt{3*3*5}$

= $4*2\sqrt{5} - 3*3\sqrt{5}$

= $8\sqrt{5} - 9\sqrt{5}$

= $-\sqrt{5}$

********************************************

Answer: $4\sqrt{5}$

<u>Step-by-step explanation:</u>

$2\sqrt{5} + 3\sqrt{5} - \sqrt{5}$

= $(2+3-1)\sqrt{5}$

= $4\sqrt{5}$

********************************************

Answer: $46\sqrt{2}$

<u>Step-by-step explanation:</u>

$4\sqrt{32} + 6\sqrt{50}$

= $4\sqrt{2*2*2*2*2} + 6\sqrt{2*5*5}$

= $4*2*2\sqrt{2} + 6*5\sqrt{2}$

= $16\sqrt{2} + 30\sqrt{2}$

= $46\sqrt{2}$

7 0

3 years ago

Erik is performing a marble experiment in math class. His teacher places an equal number of black, red, and white marbles in a b

tino4ka555 [31]

Answer:

hay luluu it's me off tic tok I'm on my other account and go with c then if not that then it's b

8 0

2 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across

Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

$\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},$

and from the right-angled triangle WAB, we have'

$\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.$

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0

3 years ago

Maya express charges 15 dollar for each person and great holiday charges fixed 84dollar and extra 12 dollar for a person. If the

goblinko [34]

Step-by-step explanation:

15 dollar for each

15*70*12

then 84*70

total amount. the above

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2 years ago

Hi I'm bored and I want to give away free points!

Helga [31]

Mystery of love and my kind of woman

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3 years ago

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