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3 years ago

Muiltiply 8x^2(x^2+2xy-6y^2) simplify your answer

Mathematics

1 answer:

stepladder [879]3 years ago

3 0

The answer would be 8x^4 + 16x^3y - 48x^2y^2

In order to find this, multiply 8x^2 by each term individually.

8x^2 * x^2 = 8x^4

8x^2 * 2xy = 16 x^3y

8x^2 * -6y^2 = -48x^2y^2

Now you can put them all in a row.

8x^4 + 16x^3y - 48x^2y^2

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What is the solution to 2logg(x) = logg8+log,(x-2)? x=-4 x=-2 X=4 X= 8

astra-53 [7]

Answer:

x = 4

which agrees with the third listed answer among the given options

Step-by-step explanation:

We can re-write the logarithmic equation using the properties of logarithms:

$2\,log(x)=log(8)+log(x-2)\\log(x^2)=log(8*(x-2))\\log(x^2)=log(8x-16)$

Therefore, the arguments of the log functions must also be equal (and we can solve for "x" by noticing that this expression is the perfect square of a binomial:

$x^2=8x-16\\x^2-8x+16=0\\(x-4)^2=0$

and for this equation to verify, x must be 4

5 0

3 years ago

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Help me with this is pls I’ll give Brainly if correct

sammy [17]

Answer:

Alrighty so number one is 5 z (x + 2y), and number two is 13x + 19y - 34z

3 0

2 years ago

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6. Michael Johnson holds the Olympic record for the men's 400m race at 43 seconds. His

vlada-n [284]

The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second

Step-by-step explanation:

We have to calculate his unit rate for both type of races

So,

Unit rate for 400m race:

Distance = 400m

Time = 43 sec

$Unit\ rate = U_1= \frac{Distance}{Time}\\=\frac{400}{43}\\=9.30\ meters\ per\ second$

Unit rate for 300m Race:

Distance = 300m

Time = 31 sec

$Unit\ Rate= U_2=\frac{300}{31}\\=9.68\ meters\ per\ second$

The difference between both unit rates is:

$U_2-U_1 = 9.68-9.30\\=0.38 => 0.4\ meters\ per\ sec$

Hence,

The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second

Keywords: Unit rate, Speed

Learn more about unit rate at:

#LearnwithBrainly

7 0

3 years ago

Suppose a regular n-gon is inscribed in a circle of radius r. Diagrams are shown for n=6, n=8, and n = 12. n = 6 n=8 n = 12 a a

m_a_m_a [10]

Answer:If an N-gon (polygon with N sides) has perimeter P, then each of the

N sides has length P/N. If we connect two adjacent vertices to the

center, the angle between these two lines is 360/N degrees, or 2*pi/N

radians. (Do you understand radian measure well enough to follow me

this far?)

The two lines I just drew, plus the side of the polygon between them,

form an isosceles triangle. Adding the altitude of the isosceles

triangle makes two right triangles, and we can use one of them to

derive the equation

sin(theta/2) = s/(2R)

where theta is the apex angle (which I said is 2*pi/N radians), R is

the length of the lines to the center (the radius of the circumscribed

circle), and s is the length of the side (which I said is P/N).

Putting those values into the equation, we have

sin(pi/N) = P/(2NR)

so that

P = 2NR sin(pi/N)

gives the perimeter of the N-gon with circumradius R.

Can we see a connection between this formula and the perimeter of a

circle? The perimeter of the circumcircle is 2*pi*R. As we increase

N, the perimeter of the polygon should get closer and closer to this

value. Comparing the two, we see

2NR*sin(pi/N) approaches 2*pi*R

N*sin(pi/N) approaches pi

You can check this out with a calculator, using big numbers for N such

as your teacher's N=1000. If you calculate the sine of an angle in

degrees rather than radians, the formula will look like

N*sin(180/N) --> pi

Step-by-step explanation:

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3 years ago

In the diagram below, AB is parallel to CD . What is the value of y?

finlep [7]

Y and the angle marked 60 degrees are internal alternate angles and are equal

so y = 60

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3 years ago

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