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Kobotan [32]
3 years ago
11

A survey of 500 likely voters showed that 385 felt that the economy was the most important national issue. Find a point estimate

(p-hat0 for p, the population proportion of voters who feel the ecomomy is the most important national issue.
A) 385
B) 0,77
C) 1.30
D) 0.08
Mathematics
1 answer:
Dovator [93]3 years ago
4 0

Answer:

Option B

Step-by-step explanation:

Given that a survey of 500 likely voters showed that 385 felt that the economy was the most important national issue.

Sample size n = 500

favor who feel the ecomomy is the most important national issue x= 385

Sample proportion = \frac{x}{n} \\=0.77

Sample proportion would be the point estimate for population proportion of voters who feel the ecomomy is the most important national issue.

Hence the point estimate (p-hat0 for p, the population proportion of voters who feel the ecomomy is the most important national issue

is 0.77

(option B)

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Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

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n₁= 6

X[bar]₁= 40.29 N

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Sample 2: Intermediate players

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Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

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