Answer:
-4,0
0,1
8,3
======
x: -4, 0, 8
f(x) = 1/4(x) + 1
Plug in x values into f(x)...
f(-4) = 0
f(0) = 1
f(8) = 3
Primary energy (PE) is an energy form found in nature that has not been subjected to any conversation or transformation process.
It is energy contained in raw fuels, and other forms of energy received as input to a system.
Brainliest answer please!
Question:
A 33 foot ladder leans against a building so that the angle between the ground and the ladder is 75º. How high does the ladder reach up the side of the building?
Round to 2 decimal places feet.
Answer:

Step-by-step explanation:
The question is illustrated using the attachment as a sketch.
We have that


Required
Determine how high the ladder is to the building
Represent the length of the ladder with L and how high the ladder is on the building with H.
The relationship between L, H and
is"

Substitute values for L and 

Make H the subject



<em>Hence, the height to which the ladder reaches is approximately 31.88ft</em>
Answer:
The solution is similar to the 2-point form of the equation for a line:
y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)
Step-by-step explanation:
Using the two points, write two equations in the unknowns of the equation of the line.
For example, you can use the equation ...
y = mx + b
Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:
b + (x1)m = (y1)
b + (x2)m = (y2)
The corresponding augmented matrix for this system is ...
![\left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26x1%26y1%5C%5C1%26x2%26y2%5Cend%7Barray%7D%5Cright%5D)
____
The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.
0 + (x2 -x1)m = (y2 -y1)
Dividing by the value in row 2 column 2 gives you the value of m:
m = (y2 -y1)/(x2 -x1)
This value can be substituted into either equation to find the value of b.
b = (y1) -(x1)(y2 -y1)/(x2 -x1) . . . . . substituting for m in the first equation