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Lina20 [59]
3 years ago
12

Please will give brainliest!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
slava [35]3 years ago
7 0

Answer:

3.5.

Step-by-step explanation:

This is given by the slope of the line

= rise/run: - consider the given point:

= 3.5/1.

inessss [21]3 years ago
5 0

Answer:

I would say 0 but i wouldnt trust me im so srry Im trying to answer as many as I can if its wrong, report me im sorry

Step-by-step explanation:

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write a linear equation that models the cost y of one person going on X rides at the fair graph the equation
Sveta_85 [38]

constant cost of 12

$1 for rides.

the number of rides you take is unknown, x

so its f(x) = 1x +12 or x+12

so if you rode 20 rides its

f(20) = 20+ 12 =32


4 0
3 years ago
Which equation has a graph that is a parabola with a vertex at (–2, 0)?
RideAnS [48]

Comparing to the standard equation, the parabola with a vertex at (-2,0) is given by:

y = (x + 2)²

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

In this problem, we have that h = -2 and k = 0, and all the options have leading coefficient a = 1, hence the equation is:

y = (x + 2)²

More can be learned about the equation of a parabola at brainly.com/question/17987697

4 0
2 years ago
Can you solve this??​
gavmur [86]

Answer:

The answer is c

Step-by-step explanation:

The middle problem is adding, the others are taking away, so C is the correct answer

3 0
2 years ago
you have 9.75 pages in your science book and 24.5 pages in your play book it takes you 1.2 minutes to read your science book and
Mazyrski [523]
Add the minutes it takes per book:-

1.2 + 0.8 = 2

You spend 2 minutes reading!
6 0
3 years ago
20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters an
Elina [12.6K]

Answer:

Two solutions: -0.12 and 1.75.

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}. Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}

\frac{-8 + 9.14}{-9.8} = -0.12

\frac{-8-9.14}{-9.8} =1.75

Hope this helped!

3 0
3 years ago
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