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nadya68 [22]
4 years ago
7

What is the slope of the line that is parallel to y=(1/2)x+3

Mathematics
1 answer:
almond37 [142]4 years ago
5 0
If the lines are parallel they have the same slopes so 1/2
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I need help with those 2
galina1969 [7]
Question 7 is a, multiply ever number by 5
question 8 is also a, multiply every number by -2
7 0
3 years ago
Solve by completing the square<br><br>x squared +14x - 51=0
Nesterboy [21]
x^2 +14x - 51=0\\ \\\Delta = b^{2}-4ac =14^{2}-4*1*(-51)=196+204=400 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-14- \sqrt{400}}{2}=\frac{-14-20}{2}= \frac{-34}{2}=-17\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-14+ \sqrt{400}}{2}=\frac{-14+20}{2}= \frac{6}{2}=3


3 0
4 years ago
Preston bought a drum set priced at 187.90. The sales tax was found by multiplying the price of the drum set by 0.08. What was t
kobusy [5.1K]

Answer:

202.90

Step-by-step explanation:

If 187.90 is the price before the sales tax, you will multiply it by the 0.08 tax which will give you 15.032. You take 15.032 and add it to 187.90 because that is the sales tax. And after you add it and round to the nearest cent you get 202.90

7 0
4 years ago
NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
Read 2 more answers
Write 108.92 in expanded form
Kitty [74]
Sorry if my writing is sloppy

5 0
3 years ago
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