Answer:
Factor this polynomial:
F(x)=x^3-x^2-4x+4
Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).
The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at
x = 1, x = 2 and x = -2. This means that
x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)
A = 1, as you can see from equation the coefficient of x^3 on both sides.
Typo:
The rational roots can be
+/-1, +/-2 and +/-4
Step-by-step explanation:
Answer:
16 m
Step-by-step explanation:
The transformations are
- (b) A vertical shift 16 units downward.
- (d) A horizontal shift 16 units to the right
<h3>How to determine the transformation?</h3>
The functions are given as:
f(x) = x
g(x)= x - 16
When a function is shifted right, the transformation rule is:
(x, y) = (x - h, y)
This means that the transformation is (d) A horizontal shift 16 units to the right
Since the parent function is a base linear function.
The transformation can also be represented as:
(x, y) = (x, k - h)
This gives
g(x)= x - 16
This means that the transformation is (b) A vertical shift 16 units downward.
Hence, the transformations are (b) and (d)
Read more about transformation at:
brainly.com/question/11709244
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The cubic function is f(x) = x^3
You need to perform three transformations to the cubic function to obtain
f(x) = - (x + 2)^3 - 5.
Those transfformations are:
1) Shift f(x) = x^3, 2 units leftward to obtain f(x) = (x + 2)^3
2) reflect f(x) = (x + 2)^3 across the x-axis to obtain f(x) = - (x + 2)^3
3) shift f(x) = - ( x + 2) ^3, 5 units downward to obtain f(x) = - (x + 2)^3 - 5
Answer:
OK SO IN MULTIPLYING INTEGERS
negative into negative is positive
positive into positive is positive
positive into negative is negative
Step-by-step explanation:
