Answer:
use -9 to multiply the first equation
use -4 to multiply the second equation.
Step-by-step explanation:
5x-4y=28.....eqn (1)×-9
3x-9y=30....eqn(2)×-4
-45x+36y=-252
-(-12x+36y=-120)
therefore, -33x÷33 =-132÷-33
x=4.
substitute (x=4) in any of the equation. I'm just going to use eqn 1.
5x-4y=28
5(4)-4y=28
20-4y=28
-4y =28-20
-4y÷-4 = 8÷-4
y=-2
so, x=4, y=-2
Note: for proof of answers substitute the answers for x and y and see if you have the same result...e.g
5(4)-4(-2)=28.
Answer:
13
Step-by-step explanation:
4 + 9
[ 9 + 2 = 11 ]
[ 11 + 2 = 13 ]
Answer:
remainder = 
Step-by-step explanation:
The remainder is the value of the subtraction of the last 2 lines in the procedure.
5x - 9
- (5x - 10)
That is
5x - 5x = 0 and - 9 - (- 10) = - 9 + 10 = 1
over the divisor x- 2 , gives
remainder = 
Answer:
110 students
Step-by-step explanation:
The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

The number of students that have taken a course in either calculus or discrete mathematics is:
