Answer:
The answer is D. 18 + (-7)
Log(2)/log(1.064) ≈ 11.17 . . . . hours
_____
The population can be given by
p(n) = p₀×1.064ⁿ . . . . where n is the number of hours
You want to find n whe p(n) = 2*p₀.
2p₀ = p₀×1.064ⁿ . . . . . . . . . . . . substitute the given information
2 = 1.064ⁿ . . . . . . . . . . . . . . . . . divide by p₀
log(2) = n×log(1.064) . . . . . . . . take logs to make it a linear equation
log(2)/log(1.064) = n . . . . . . . . divide by the coefficient of n
Answer:
<h2>-8</h2>
Step-by-step explanation:
![4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8](https://tex.z-dn.net/?f=4-3%5B6-2%284-3%29%5D%5C%5C%5C%5CFollow%5C%3Athe%5C%3APEMDAS%5C%3Aorder%5C%3Aof%5C%3Aoperations%5C%5C%5C%5C%5Cmathrm%7BCalculate%5C%3Awithin%5C%3Aparentheses%7D%5C%3A%5Cleft%5B6-2%5Cleft%284-3%5Cright%29%5Cright%5D%20%3A%204%5C%5C%5C%5C%3D4-3%5Ctimes%5C%3A4%5C%5C%5C%5C%5Cmathrm%7BMultiply%5C%3Aand%5C%3Adivide%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A3%5Ctimes%5C%3A4%5C%3A%3A%5Cquad%2012%5C%5C%3D4-12%5C%5C%5C%5C%5Cmathrm%7BAdd%5C%3Aand%5C%3Asubtract%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A4-12%5C%3A%5C%5C%5C%5C%3A%5Cquad%20-8)
D, because there are several students that are in your school. There would be many different answers.
