2 quarters, 7 pennies
5 dimes, 7 pennies
10 nickels, 7 pennies
Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
Sorry in order to answer this I need the picture of the 4 triangles
The smallest degree that you can rotate a pentagon is 36 degrees
50% of 620 is half of 620.
Writing 50% of 620 is 50%. (Or 310 if you wanted to know half of 620)
