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3 years ago

I NEED HELP ON THIS PLEASE ASAP

Mathematics

1 answer:

Ivahew [28]3 years ago

3 0

Answer:

No Correlation

Step-by-step explanation:

There's no relationship between the points; the variables are not increasing or decreasing

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Which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 + 2x – 1 into the quadratic formula bel

lidiya [134]

0 = 4x²<span> + 2x – 1

this equation is already ordered by degree, so it's in the correct form. the standard form of a parabola is like so: 0 = A</span>x² + Bx - C

that's exactly how you plug values into the quadratic formula. the coefficient for your squared value, A, is 4. take the coefficients from your other numbers as well.

a = 4
b = 2
c = -1

3 0

3 years ago

Read 2 more answers

Simplify for ez fast points!

soldier1979 [14.2K]

Answer:

0.027

Step-by-step explanation:

0.1×0.1×0.1=0.027----->2.7×10^-2

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3 years ago

A sample of tritium-3 decayed to 94.5% of its original amount after a year.

Zolol [24]

(a) If $y(t)$ is the mass after $t$ days and $y(0) = A$ then $y(t) = Ae^{kt}.$

$y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945$

$\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\ ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}$

(b)
$Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}$

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3 years ago

Three-quarters of the students that Maria surveyed stated that they liked to sleep in on Saturday morning. If 24 of the students

OLga [1]

Answer:

I think it’s C

Step-by-step explanation:

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harkovskaia [24]

0.1 mile per min

Step-by-step explanation:

lol i’m fye

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