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Answer:
$4000000
Step-by-step explanation:
Given data :
200000 shares at $10 par common stock outstanding
market price of stock = $12 per share
increased par value of stock = $10 ( $20)
Black's paid-in capital--excess of par account = $4000000.
The balance in Black's paid-in capital--excess of par account immediately after the reverse stock spit will be $4000000 because the increased par value of stock from $10 to $20 will be reversed back immediately after the reverse stock hence the paid-in capital--excess before stock split = paid-in capital --excess immediately after reverse stock split
sum = x(n+1)/2
where x is the number of the term ( in this case 52)
n is the last number in the series( which is not given in the problem)
Answer:
10,000
Step-by-step explanation:
"The number who have been vaccinated against both is twice the number who have been vaccinated only against mumps."
Let b = number of children vaccinated against both.
Let m = number of children vaccinated only against mumps.
b = 2m
"If 5,000 have been vaccinated against both"
5000 = 2m
m = 2500
5000 children are vaccinated against both.
2500 children are vaccinated only against mumps.
The total number vaccinated against mumps is the number vaccinated only against mumps plus the number vaccinated against both:
2500 + 5000 = 7500
"the number of children who have been vaccinated against rubella is twice the number who have been vaccinated against mumps."
total number of children vaccinated against rubella = 2 * 7500 = 15,000
5000 of those children are vaccinated against both.
15,000 - 5000 = 10,000
10,000 children are vaccinated only against rubella.
Answer: 10,000
