Hello there! The area of the triangle portion is 11 square units, the area of the rectangle portion is 77 square units, and the area of the entire figure is 88 square units.
To find the area of the triangle, we can follow the formula:
A = LW/2 (which means length x width divided by 2)
Given the formula:
2 • 11 = 22
22 divided by 2 gives us 11 square units.
To find the area of the rectangle portion, we can follow the area formula:
A = LW (which means area = length x width)
Given the formula:
7 • 11 = 77 square units
To find the area of the whole figure, we add the areas of both isolated shapes:
11 + 77 = 88 square units.
Therefore, our area for the entire figure is 88 square units. If you need any extra help, let me know and I will gladly assist you.
6/(x-8)=2/(x+6)
times both sides by (x-8)(x+6)
6(x+6)=2(x-8)
distribute
6x+36=2x-16
minus 2x both sides
4x+36=-16
miinus 36 both sides
4x=-52
divide both sides by 4
x=-13
Answer:
7 square units
Step-by-step explanation:
As with many geometry problems, there are several ways you can work this.
Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.
The applicable formulas are ...
area of a trapezoid: A = (1/2)(b1 +b2)h
area of a triangle: A = (1/2)bh
So, our areas are ...
AQRS = AWSQE - AWSR - AEQR
= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)
Factoring out 1/2, we have ...
= (1/2)((2+5)·4 -2·2 -5·2)
= (1/2)(28 -4 -10) = 7 . . . . square units
