If A, B and C are collinear, then
1) if B is between A and C:
AC = AB + BC
AC = 48 + 22 = 70
2) if C is between A and B:
AB = AC + BC
48 = AC + 22 |-22
AC = 26
3) if A is between B and C:
BC = AB + AC
22 = 48 + AC |-48
AC = - 26 < 0 FALSE
Answer:
if B is between A and C, then AC = 70
if C is between A and B, then AC = 26
Answer:
x=7
Step-by-step explanation:
Add 10 to both sides to isolate x.
4x=28
x=7
Answer:
B
Step-by-step explanation:
x² - 12x + 11 = 0 ( subtract 11 from both sides )
x² - 12x = - 11
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 6)x + 36 = - 11 + 36
(x - 6)² = 25 ( take square root of both sides )
x - 6 = ± 
= ± 5 ( add 6 to both sides )
x = 6 ± 5
Then
x = 6 - 5 = 1 ⇒ (1, 0 )
x = 6 + 5 = 11 ⇒ (11, 0 )
$500 x 0.85 = 425
$425 x 0.85 = 361.25
$361.25 x 0.85 = 307.10
$307.1 x 0.85 = 261
$261 x 0.85 = 221.85
The two lines start at the same point outside the circle, using the intersecting Secants theorem, When you multiply the two dims for each line together, they are equal
For A:
5 * (5+x) = 6 * (6+4)
25 + 5x = 60
5x = 35
x = 35/5
x = 7
For B:
5 * (5+ 3) = 4 * ( 4+x)
40 = 16 + 4x
4x = 24
x = 24/4
x = 6
