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dusya [7]
3 years ago
7

Round 5.53 to one decimal place

Mathematics
1 answer:
Bond [772]3 years ago
3 0
5.5, when rounding a number, if the second digit is below 5 you round it down, in this case, 5.53, if its 5.5 or above, for example 5.56, you would round it up to 5.6
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1 1/4 cups of flour divided by 1/8 cups of butter
Dimas [21]
5/32 is the answer
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8 0
3 years ago
Read 2 more answers
Find x. (Use pic for more info)
V125BC [204]

Answer:

x=75

Step-by-step explanation:

Hey There!

If you didn't know the exterior angle of a triangle is equal to the sum of the opposite interior angles of a triangle

So essentially what I'm saying is that

2x-5=70+x

step 1 add 5 to each side

-5+5 cancels out

70+5=75

now we have

2x=70+x

step 2 subtract x from each side

x-x cancels out

2x-x=x

we're left with

x=75

8 0
3 years ago
Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function f(x)=(x^{2},4x,z^{2}) and curve C is ellipse of equation

16x^{2} + 4y^{2} = 3

Theory: Stokes Theorem is given by:

I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx

Where, Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Also, f(x) = (F1,F2,F3)

\hat{N} = grad(g(x))

Using Stokes Theorem,

Surface is given by g(x) = 16x^{2} + 4y^{2} - 3

Therefore, tex]\hat{N} = grad(g(x))[/tex]

\hat{N} = grad(16x^{2} + 4y^{2} - 3)

\hat{N} = (32x,8y,0)

Now,  f(x)=(x^{2},4x,z^{2})

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

I= \int \int\limits {Curl f\cdot \hat{N} } \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0
3 years ago
What are the solutions of -x^2+4x=x-4
Stolb23 [73]

Answer:

x = -1 and x = 4

Step-by-step explanation:

Step 1:  Get everything to one side of the equation so it's set equal to zero..

-x² + 4x = x - 4  becomes...

  -x² + 3x + 4 = 0        (subtract x and add 4 to both sides)

    x² - 3x - 4 = 0  (divide both sides by -1, we want the x² term to be positive)

   (x - 4)(x + 1) = 0          (factor)

      so

x - 4 = 0,    then x = 4

and

x + 1 = 0,   then x = -1  

8 0
3 years ago
Identify the center and radius of the circle with the following equation:<br> 〖(x+3)〗^2+〖(y-1)〗^2=81
kirill115 [55]

Answer:

centre (3 ,-1) , r=9

Explanation:

The standard form of the equation of a circle is.

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

a

a

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−−

where (a,b) are the coordinates of the center and r , the radius.

For the given equation: a = 3 , b = -1 and r = 9

hence centre = (3 ,-1) and radius = 9

Step-by-step explanation:

4 0
2 years ago
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