I don’t know if this is right but the way I did it I got 7.5
Answer:
P=3T-50
Step-by-step explanation:
Form the given four values we can assume a linear relationship between profit and the no of tickets sold.
Let the equation corresponding to that be some P=aT+b.
Now substitute the first set of values(100,50) in the above equation we get
100=50a+b.
Now substituting second set of values (100,250) we get 250=100a+b.
Let these equations be eq1 and eq2.
Now substract eq1 from eq2 we get 50a=150 or a=3.
Substitite value of a in one of the equations we get b=-50.
∴P=3T-50
I'll help but what are u supposed to do
Answer:
The bus was traveling faster.
Step-by-step explanation:
Remember; Distance = Speed * Time, or D = S * T
Steps for each problem;
- set up the equation
-substitute in the given values
- solve
Car; Distance = Speed * Time
225 = Speed * 15
15 mps = Speed
Bus; Distance = Speed * Time
500 = Speed * 25
20mps = Speed
Car ... Bus
15 < 20
The bus was traveling faster.
