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Thepotemich [5.8K]
3 years ago
6

Helpppp plsssss!!

Mathematics
1 answer:
aivan3 [116]3 years ago
8 0

If the lines are parallel, the have to have the same slope

so if the red line has a slope of 2/5, the green line will have a slope of  2/5

Answer: 2/5

Choice B

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How to do label tape diagram to subtract tens
irinina [24]

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is that what you meant


4 0
3 years ago
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After doing some work in the house, Bob and Carol want to put a concrete patio on the side of the house to keep people from trac
12345 [234]

Answer:

V=3.098 yd³

Step-by-step explanation:

To answer this question we need to work with formula of the Volume of rectangular prism, the patio. Once it is required 1 inch deep. Some relations will be useful.

As 1 yard = 1 feet/3

1 yard = 1 inch/36

1 feet=12 inches

a) 23 feet 9 inches

23 ft 9''=23 +9/12=23.75 ft

b)10 feet  1 inch

10 feet  1" = 10ft + 1/12=10.083 ft

c)4 inches: 4/12 =0.33

V= w.l.h

V=23.75*10.083*0.33=79.025 ft³

Converting from cubic yard to cubic feet:

V≈79.025 : 27 yd³=2.926 yd³

Considering the possible spillage due to uneven base. ( adding 5%of V)

V≈ 2.92+0.05*(2.92)=3.098 yd³

4 0
3 years ago
Read 2 more answers
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
What property is being shown? <br><br> 5 + (6 + 3) = (5 + 6) + 3
telo118 [61]

Hello I believe that the property is comuutative thank you


5 0
3 years ago
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A cone and a cylinder have congruent height and base bases. The volume of the cone is 18m squared. What's the volume of the cyli
zzz [600]
Short answer 3 times as much = 54 m^3 <<<<< answer

The volumes are krelated by k So solve for k

Volume of Cylinder = k Volume of the cone.
pi r^2 h = k(1/3 pi r^2 h)  Since you know that r is the same in both and so is h they divide out.
divide by h
pi r^2  = k (1/3 pi r^2 Divide by pi
r^2 = k (1/3 r^2 ) Divide by r^2
1 = k (1/3) multiply by 3
3 = k

The volume will be 3 times as much.as the cone.
3 * 18 = volume of cylinder.
54 <<<< volume of cylinder.


8 0
3 years ago
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