Answer:
Economical thickness is 3.823 units
<u>Explanation:</u>
Insulation Annual Cost=2000+650t
Energy cost of heat loss=19000*(t) ^ (-0.5)
Total annual Cost=2000+650t+19000t ^ (-0.5)
<u>We need to find optimum value of thickness such that Total annual cost is minimum.</u> Therefore, we have dC/dt=0 and d^C/dt^2>0
Equation 1)
...........dC/dt=650-9500t^-1.5
Equation 2)
...........d^C/dt^2=4750t^-1.5
<u>For 1) </u>we have 650-9500t^(-1.5)=0
650/9500=t^-0.5
190/13=t^0.5
t=3.823 units
Hence, if we check for obtained value of "t" we have second order condition met then
d^2C/dt^2=4750*(3.823)^(-1.5)=635.4584551>0 by the way for any value of "t">0 we will suffice second order condition
Hence, economical thickness is 3.823 units
<span>Put all of these numbers in a line...obviously, don't put ALL of them, but enough so you can see what you're doing.
1 + 2 + 3 + ... + 297,624,985
Now put all these numbers BACKWARDS underneath that.
1 + 2 + 3 + ... + 297,624,985
297,624,985 + 297,624,984 + 297,624,983 + ... + 1
Now add the first series to the second, and you'll see that they add up to:
297,624,986 + 297,624,986 + 297,624,986 + ...297,624,986
Since there were 297,624,985 terms, the total sum here is
297,624,986 * 297,624,985
But since you added it twice, you divide it by two:
148,812,493 * 297,624,985
This is 44,290,315,996,937,605, so...yes, it is MUCH larger.</span>
Answer: See explanation
Explanation:
a. Determine the annual parking lot staff budget for school days, nonschool days, and total.
For school days:
Number of staff required per day = 3000/20 = 15
Number of staff days per year = 15 × 165 = 2475
Annual parking lot staff budget = 2475 × $110 = $272250
For non school days:
Number of staff required per day = 8000/20 = 40
Number of staff days per year = 40 × 200 = 8000
Annual parking lot staff budget = 800 × $110 = $880,000
Total annual parking lot staff budget = $272250 + $880000 = $1152250
b. Determine the parking revenue for school days, nonschool days, and total.
For school days:
Total number of vehicles per year = 3000 × 165 = 495000
Parking revenue = 495000 × $10 = $4950000
For non school days:
Total number of vehicles per year = 8000 × 200 = 1600000
Parking revenue = 1600000 × $10 = $16000000
Total parking revenue = $4950000 + $16000000 = $20950000
c. If depreciation expense and other expenses for running the parking lot were estimated to be $2 million per year, determine the parking lot's budgeted profit.
Parking revenue = $20,950,000
Less: Parking lot staff payroll = $1152250
Less: Depreciation and other expenses = $2000000
Budgeted profit = $177977500
The Sarbanes-Oxley Act of 2002 requires the CEO (Chief
Executive Officer) and the CFO (Chief Financial Officer) to personally certify
the accuracy of the financial statement that the company has filed with the
Securities and Exchange Commission as
members of senior management.