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uysha [10]
3 years ago
10

If the molecule C6H12 does not contain a double bond, and there are no branches in it, what will its structure look like?

Chemistry
1 answer:
NARA [144]3 years ago
5 0
I have attached a photo of the structure. 
You can get better at solving problems like this by practicing a lot! 




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Given that a for HCN is 6. 2×10^−10 at 25 °C. What is the value of b for cn− at 25 °C?
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If Ka for HCN is 6. 2×10^−10 at 25 °C, then the value of Kb for cn− at 25 °C is 1.6 × 10^(-5).

<h3>What is base dissociation constant? </h3><h3 />

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

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Given,

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The correlation between base dissociation constant and acid dissociation constant is

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Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{6.2×10^(-10) }

= 1.6× 10^(-5)

Thus, the value of base dissociation constant at 25°C is 1.6 × 10^(-5).

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<h2><u>Answer</u> :</h2>

The most appropriate option is :

\hookrightarrow \bf2. \:  \mathrm{ \underline{oxygen \:  \: and \:  \: silicon}}

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\circ  { \underline{ \boxed{ \sf{ \color{green}{ \mathrm{hope \:  \: it \:  \: helps \:  \: you .....}}}}}}∘

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