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Tju [1.3M]
3 years ago
15

What is extensibility?​

Chemistry
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

Extensibility is a software engineering and systems design principle that provides for future growth.

Explanation:

hope ot helps good day

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Iron and aluminim are examples of _________. a. pure substances b. compounds
Ierofanga [76]

Answer:

compounds

Explanation:

8 0
2 years ago
Read 2 more answers
What is the pH of a 5.09 x 10-5 M solution of NaOH?
Varvara68 [4.7K]

<u>Answer:</u> The pH of the solution is 9.71

<u>Explanation:</u>

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.

We are given:

pOH of the solution = 7.2

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOh of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=5.09\times 10^{-5}M

Putting values in above equation, we get:

pOH=-\log(5.09\times 10^{-5})\\\\pOH=4.29

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-4.29=9.71

Hence, the pH of the solution is 9.71

7 0
3 years ago
A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

4 0
3 years ago
Science need ko po ng help di mo ako kase matalino salamat po
Lorico [155]

Answer:

1.An initial observation is the measurement that you take before you start any process that might cause a change. When you compare your subsequent observations with the initial one, you will see whether any change has taken place, and you will be able to measure the change.

Explanation:

D ko po alam yung iba

6 0
3 years ago
Can anyone help me with any of the questions
Dafna11 [192]
Use the chart to help you look carefully at the numbers and the volumes to figure the questions out hope this helps
7 0
3 years ago
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