Number of molecules in 1 dm³ Oxygen = 2.71 x 10²²
<h3>Further explanation</h3>
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
1 dm³ of oxygen = 1 L Oxygen
n=mol=0.045
No = 6.02.10²³
The answer is C. Glue gun melts a glue stick.
Before............................
Answer:
12.9 L Kr
General Formulas and Concepts:
<u>Chemistry - Gas Laws</u>
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
0.575 mol Kr
<u>Step 2: Identify Conversions</u>
1 mol= 22.4 L at STP
<u>Step 3: Convert</u>
<u />
= 12.88 L Kr
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
12.88 L Kr ≈ 12.9 L Kr
Answer:966.45ml
Explanation:
Using Charles law.. V1/T1=V2/T2
V1=535ml
T1=-25+273
=248k
T2= 175+273=448k
V2=?
V2= V1*T2/T1
V2=535*448/248
V2=239680/248
V2=966.45ml
