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Bess [88]
3 years ago
6

3. A property that does NOT depend on the amount of matter such as density, color, temperature. A. Intensive B. Extensive​

Chemistry
1 answer:
pshichka [43]3 years ago
5 0

Answer:

extensive

hope it helps!

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4. One gram of of ............... contains one type of atoms. a. iron b. ammonia c. hydrogen chloride d. water​
patriot [66]

Answer: hydrogen chloride.

Explanation:

7 0
2 years ago
Please help.
denpristay [2]

Answer:

The bowling ball has more kinetic energy than the tennis ball

Explanation:

Using the formula 1/2 mass × acceleration we found that the tennis ball had a kinetic energy of 0.75 while the bowling ball had a kinetic energy of 10.5 hence the bowling ball has the ability to do more work

5 0
2 years ago
A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

Q_1=-Q_2

Mass of steel= m_1

Specific heat capacity of steel = c_1=0.452 J/g^oC

Initial temperature of the steel = T_1=2.00^oC

Final temperature of the steel = T_2=T=21.50^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2= 105 g

Specific heat capacity of water=c_2=4.18 J/g^oC

Initial temperature of the water = T_3=22.00^oC

Final temperature of water = T_2=T=21.50^oC

Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))

On substituting all values:

(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}

<h3>25.0 grams is the mass of the steel bar.</h3>
3 0
3 years ago
Read 2 more answers
a closed flask of air (0.250 L) contains 5.00 "puffs" of particles. The pressure probe on the flask reads 93 kPa. A student uses
Sergio039 [100]

Answer: New pressure inside the flask would be 148.8 kPa.

Explanation: The combined gas law equation is given by:

PV=nRT

As the flask is a closed flask, so the volume remains constant. Temperature is constant also.

So, the relation between pressure and number of moles becomes

P=n\\or\\\frac{P}{n}=constant

\frac{P_1}{n_1}=\frac{P_2}{n_2}

  • Initial conditions:

P_1=93kPa\\n_1=5\text{ puffs}

  • Final conditions: When additional 3 puffs of air is added

P_2=?kPa\\n_2=8\text{ puffs}

Putting the values, in above equation, we get

\frac{93}{5}=\frac{P_2}{8}\\P_2=148.8kPa

3 0
3 years ago
Plz help me with this pt.3
hichkok12 [17]

Answer:

I think the answer is

Our solar system will always be part of the Milky Way.

7 0
3 years ago
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