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3 years ago

I am a odd number less than 100 and a multiple of 15.The sum of my digits is 12.What number am I.

Mathematics

2 answers:

Reptile [31]3 years ago

7 0

The answer is 75. 7+5=12 and it’s less than 100

lutik1710 [3]3 years ago

6 0

The number is 75
15*3=75
75<100
7+5=12
75 is odd

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Bought a new car lately? The following table presents the number of vehicles sold in a certain country by several manufacturers

ella [17]

Answer:

The Relative Frequency Table is:

Manufacturer Relative Frequency

General Motors 0.242

Ford 0.208

Chrysler LLC 0.148

Toyota 0.177

Honda 0.116

Nissan 0.109

Step-by-step explanation:

To find out the relative frequency we need to use the formula:

Relative Frequency = Frequency / Sum of All Frequencies

We can find the sum of all the frequencies by adding all the sales for the year 2013.

Sum of Frequencies for 2013 = 225,650 + 194,068 + 138,085 + 164,423 + 107,526 + 101,113

Sum of Frequencies for 2013 = 930865 cars

Now we can compute the relative frequencies for each of the manufacturers as follows:

General Motors: 225650/930865 = 0.242

Ford: 194068/930865 = 0.208

Chrysler LLC: 138085/930865 = 0.148

Toyota: 164423/930865 = 0.177

Honda: 107526/930865 = 0.116

Nissan: 101113/930865 = 0.109

Relative Frequency Distribution Table for the 2013 sales:

Manufacturer Relative Frequency

General Motors 0.242

Ford 0.208

Chrysler LLC 0.148

Toyota 0.177

Honda 0.116

Nissan 0.109

3 0

3 years ago

CD is a perpendicular bisector of chord AB and a chord through CD passes through the center of a circle. Find the diameter of th

Keith_Richards [23]

Answer:

$12\frac{1}{5}$ in

Step-by-step explanation:

I don't know if you got this pic but this is the answer for this pic

5 0

2 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

What is the solution to -2(3x - 9) + 5x = -10?

sweet-ann [11.9K]

-2(3x - 9) + 5x = -10
-6x + 18 + 5x = -10
-6x + 5x = -10 - 18
-x = -28
x = 28 <===

6 0

3 years ago

A shopping mall parking garage charges $2 for the first half hour and $1.20 for each additional half hour (even if it is under 3

Neko [114]

You can park in the garage for 5 hours 30 minutes

Solution:

Given that, shopping mall parking garage charges $2 for the first half hour and $1.20 for each additional half hour (even if it is under 30 minutes)

Therefore,

Cost for first half an hour = $ 2

Cost for each additional half an hour = $ 1.20

Let "x" be the number of each additional half hour

Therefore, total cost to pay is given as:

Total cost = Cost for first half an hour + (Cost for each additional half an hour)(number of each additional half hour)

Total cost = 2 + 1.20x

Given you have $ 8 in cash

$8 = 2 + 1.20x\\\\1.20x = 8 - 2\\\\1.20x = 6\\\\x = \frac{6}{1.20}\\\\x = 5$

Total hours parked = first half an hour + 5

Thus you can park in the garage for 5 hours 30 minutes

4 0

3 years ago