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stiv31 [10]
4 years ago
15

The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random

Mathematics
1 answer:
ser-zykov [4K]4 years ago
6 0

Answer:

Probability that both eggs are cracked is 0.0001.

Step-by-step explanation:

We are given that the probability that an egg on a production line is cracked is 0.01.

Two eggs are selected at random  from the production line.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......

where, n = number trials (samples) taken = 2 eggs

            r = number of success = both eggs are cracked

            p = probability of success which in our question is probability that

                 an egg on a production line is cracked, i.e; p = 0.01

<u><em>Let X = Number of eggs on a production line that are cracked</em></u>

So, X ~ Binom(n = 2, p = 0.01)

Now, Probability that both eggs are cracked is given by = P(X = 2)

                P(X = 2) =  \binom{2}{2} \times 0.01^{2} \times (1-0.01)^{2-2}

                              =   1\times 0.01^{2} \times 0.99^{0}

                              =  0.0001

<em>Therefore, probability that both eggs are cracked is </em><em>0.0001</em><em>.</em>

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3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

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Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

3 + 12 + 48 + 192 + 768

The expression can be written as:

3 \to 3*4^{0 --- 0

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48 \to 3 * 4^{2 --- 2

192 \to 3 * 4^{3 ---- 3

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For the nth term, the expression is:

Term = 3 * 4^{n ---- n

So, the summation is:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

Solving (b):

4 + 32 + 256 + 2048 + 16384

The expression can be written as:

4 \to 4 * 8^0 --- 0

32 \to 4 * 8^1 ---- 1

256 \to 4 * 8^2 --- 2

2048 \to 4 * 8^3 ---- 3

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For the nth term, the expression is:

Term \to 4 * 8^n ---- n

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Solving (c):

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The expression can be written as:

2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

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For the nth term, the expression is:

Term \to 2 * 3^n ---- n

So, the summation is:

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

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3 \to 3 * 5^0 --- 0

15 \to 3 * 5^1 ---- 1

75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

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