Ask question

Ask question

All categories

3 years ago

10

I really need help with this math problem.

1 answer:

Art [367]3 years ago

3 0

Answer D.

$(36\dfrac{3}{4} +36\dfrac{3}{8} +37\dfrac{1}{2} +z):4=36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\109\dfrac{13}{8}+z=4\cdot36+4\cdot\dfrac{5}{8}\\\\\\110\dfrac{5}{8}+z=144+\dfrac{20}{8} \\\\\\z=144+\dfrac{20}{8} -110-\dfrac{5}{8}\\\\\\z=34+\dfrac{15}{8}\\\\\\z=34+1\dfrac{7}{8}\\\\\\z=35\dfrac{7}{8}$

You might be interested in

PLZZZ LOOK AT THE PHOTO PROVIDE HELPPPP I NEEED HELPPPPPPPPPOPP

hoa [83]

Answer:

OH MY GOSH I DON'T KNOW BUT GL! WISH YOU THE BEST AAAAA-

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The graph represents the fees in thousands of dollars, y, depending on the amount invested in millions, x, with one financial in

sammy [17]

The answer is [1,20)

6 0

3 years ago

Question 2 Evaluate the expression 2(x - 3) + 3y when x = 5 and y = 3. Mark the correct answer.

8_murik_8 [283]

Answer:

A. 13

Step-by-step explanation:

2(x - 3) + 3y

2(5 - 3) + 3×3

2× 2 + 3×3

4 + 9

13

7 0

3 years ago

Read 2 more answers

Do any one know the answer 8X + 4 - 6x + 7*

Lena [83]

Answer:
2x+11

Explanation: it’s the answer:)

5 0

3 years ago

Read 2 more answers

Need help with inscribed angles If M

Bogdan [553]

Given:

In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and $m\angle BCD=30^\circ$ .

To find:

The $m\angle AOB$ .

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

We have, DC is parallel to BA and BC is the transversal line.

$\angle OBA\cong \angle BCD$ [Alternate interior angles]

$m\angle OBA=m\angle BCD$

$m\angle OBA=30^\circ$

In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

We know that base angles of an isosceles triangle are congruent.

$\angle OAB\cong \angle OBA$ [Base angles of an isosceles triangle]

$m\angle OAB=m\angle OBA$

$m\angle OAB=30^\circ$

In triangle AOB,

$m\angle OAB+m\angle OBA+m\angle AOB=180^\circ$

$30^\circ+30^\circ+m\angle AOB=180^\circ$

$60^\circ+m\angle AOB=180^\circ$

$m\angle AOB=180^\circ-60^\circ$

$m\angle AOB=120^\circ$

Therefore, the measure of angle AOB is 120 degrees.

6 0

3 years ago