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sveta [45]
3 years ago
10

I really need help with this math problem.

Mathematics
1 answer:
Art [367]3 years ago
3 0

Answer D.

(36\dfrac{3}{4} +36\dfrac{3}{8} +37\dfrac{1}{2} +z):4=36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\109\dfrac{13}{8}+z=4\cdot36+4\cdot\dfrac{5}{8}\\\\\\110\dfrac{5}{8}+z=144+\dfrac{20}{8} \\\\\\z=144+\dfrac{20}{8} -110-\dfrac{5}{8}\\\\\\z=34+\dfrac{15}{8}\\\\\\z=34+1\dfrac{7}{8}\\\\\\z=35\dfrac{7}{8}

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6 0
3 years ago
Read 2 more answers
3 people work full time together on a project, but their total time on the project is to be equivalent to only 1 person working
NikAS [45]
Let x = the amount of time that the third person needs to work on the job to add up to one

1 = 1/2 + 1/3 + x

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To subtract the fractions we need to put them all over a common denominator. Let's use 3*2 = 6 as the denominator; so 1 = 6/6, 1/2 = 3/6, 1/3 = 2/6:

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3 years ago
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spin [16.1K]

Answer:

16/15

Step-by-step explanation:

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