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Ksivusya [100]
3 years ago
15

Can sumone plzhelp..Apply the distributive property to factor out the greatest common factor of all three terms .

Mathematics
2 answers:
Nat2105 [25]3 years ago
6 0

Answer:

3(3a - 6b + 7c )

Step-by-step explanation:

The greatest common factor of 9, 18 and 21 is 3

Factor out 3 from each term

9a - 18b + 21c

= 3(3a - 6b + 7c) ← in factored form

Bad White [126]3 years ago
4 0

Answer:

3(3a - 6b + 7c)

Step-by-step explanation:

Write each term as a multiplication of its factors. Then see which factors are in common to all terms.

9a - 18b + 21c =

= 3 * 3 * a - 2 * 3 * 3 * b + 3 * 7 * c

The common factors are shown below in bold:

= 3 * 3 * a - 2 * 3 * 3 * b + 3 * 7 * c

The only common factor is 3.

Now use the distributive property to factor out a 3.

= 3(3 * a - 2 * 3 * b + 7 * c)

Now multiply each term in parentheses again.

= 3(3a - 6b + 7c)

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Answer:  c) 3

<u>Step-by-step explanation:</u>

Plug in y = -9 and the given x-value to see if it makes a true statement.

a) -4.5 falls in the piecewise function x < -3  --> y = -x

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b) -3 falls in the piecewise function -3 ≤ x ≤ -2  --> y = 2x

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d) 9 falls in the piecewise function x > -2 --> y = -x²

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