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Ksivusya [100]
3 years ago
15

Can sumone plzhelp..Apply the distributive property to factor out the greatest common factor of all three terms .

Mathematics
2 answers:
Nat2105 [25]3 years ago
6 0

Answer:

3(3a - 6b + 7c )

Step-by-step explanation:

The greatest common factor of 9, 18 and 21 is 3

Factor out 3 from each term

9a - 18b + 21c

= 3(3a - 6b + 7c) ← in factored form

Bad White [126]3 years ago
4 0

Answer:

3(3a - 6b + 7c)

Step-by-step explanation:

Write each term as a multiplication of its factors. Then see which factors are in common to all terms.

9a - 18b + 21c =

= 3 * 3 * a - 2 * 3 * 3 * b + 3 * 7 * c

The common factors are shown below in bold:

= 3 * 3 * a - 2 * 3 * 3 * b + 3 * 7 * c

The only common factor is 3.

Now use the distributive property to factor out a 3.

= 3(3 * a - 2 * 3 * b + 7 * c)

Now multiply each term in parentheses again.

= 3(3a - 6b + 7c)

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Simplify 4 + 10 ÷ (–2).
Gnesinka [82]

Answer:

-1 Your answer is A

Step-by-step explanation:

4+ 10/-2=-1

10/-2=-5

4+-5=-1

3 0
3 years ago
Read 2 more answers
Triangle ABC has vertices A(-3,0) B(0,6) C(4,6). Find the equations of the three medians of triangle ABC
Mariana [72]

Answer:

1.y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}

2.y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}

Step-by-step explanation:

A(−3, 0), B(0, 6), and C(4, 6)

using the midpoint formula: (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) we can find all of their midpoint which is necessary to complete question 1 and 2

Mid AB=(-1.5, 3), Mid BC=(2, 6), Mid AC=(0.5,3)

Next, we have to find the slope of from the vertex and the midpoint of each side. We use the slope formula: \frac{y_2-y_1}{x_2-x_1}.

You would get -6, 6/5, and 6/11.

Next you substitute in the coordinates for the equation of each for example: y=-6x, you switch in the set of cords AB which is (-1.5, 3). 3=-6(-1.5)+z and find that z=6, so the equation is y=-6x+6. As for the rest, repeat the same process until you find all 3 cords. You should get an answer of y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}

For question 2,

The line has to be perpendicular bisector to the midpoint, signifying that it has to split 2 angles into congruent angles and a side into half. In order to do that we need to first find the opposite reciprocal of each side's slope. Which means we need to once again use the slope formula and get the opposite reciprocal by -\frac{1}{slope}. For all the opposite reciprocal slopes you get will be incorporated into the final formulas. That gives us the slopes of -1/2, 0 and -7/6. Then do the same process of matching cords with these incomplete equations and you can find the final equations of y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}

I hope that helped with your question!! :)

Also I'm an RSM student too and I didn't know how to do them before so I searched it up.

6 0
2 years ago
Helpppp quickk pleassee I’m being timeddd
Alex

<u>Given</u>:

The given graph represents the cost of the Kayak's rental per hour.

The coordinates are (2,30) and (3,45)

We need to determine the unit rate of renting per hour.

<u>Unit rate of renting:</u>

The unit rate of renting can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the coordinates (2,30) and (3,45), we get;

m=\frac{45-30}{3-2}

Simplifying, we get;

m=\frac{15}{1}

Dividing, we get;

m=15

Thus, the unit rate for renting a Kayak is $15 per hour.

7 0
3 years ago
Pls help will give brainliest
BaLLatris [955]

Answer:

247 ft is the correct answer

6 0
2 years ago
Read 2 more answers
What is the LCM of 13/16a^3b^3, 11/30a^5b
vichka [17]

Answer:

The L.C.M of given numbers is \frac{143}{240}a^5b^3.

Step-by-step explanation:

The given expressions are

\frac{13}{16}a^3b^3

\frac{11}{30}a^5b

The factors of given expressions are

\frac{13}{16}a^3b^3=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b

\frac{11}{30}a^5b=\frac{11}{15}\times \frac{1}{2}\times a\times a\times a\times a\times a\times b

L.C.M.=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b\times \frac{11}{15}\times a\times a

L.C.M.=\frac{143}{240}\times a^5\times b^3

L.C.M.=\frac{143}{240}a^5b^3

Therefore, the L.C.M of given numbers is \frac{143}{240}a^5b^3.


8 0
3 years ago
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