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AleksandrR [38]
3 years ago
11

What is the greatest common factor of 14 56 63?

Mathematics
1 answer:
olga55 [171]3 years ago
6 0
14: 1 × 14
      2 × 7

56: 1 × 56
      2 × 28
      4 × 14
      7 × 8

63: 1 × 63
      3 × 21
      7 × 9
GCF(14, 56, 63) = 7
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For each x value, add 3 to get y values.
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3 years ago
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A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
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Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

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In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

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P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

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3 years ago
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Maths question algebra
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Step-by-step explanation:

=

38.64=9.2h/2

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4 0
3 years ago
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