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Sindrei [870]
3 years ago
11

The time t required to drive a certain distance varies inversely with the speed r. if it takes 4 hours to drive the distance at

35 miles per hour, how long it will take to drive the same distance at 45 miles per hour?
A. about 3.11 hours
B. 140 hours
C. about 5.14 hours
D. 393.75 hours
Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0
\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \stackrel{\textit{time \underline{t} required to drive a certain distance varies inversely with the speed \underline{r}}}{t=\cfrac{k}{r}}
\\\\\\
\textit{we also know that }
\begin{cases}
t=4\\
r=35
\end{cases}\implies 4=\cfrac{k}{35}\implies 4(35)=k
\\\\\\
140=k\qquad therefore\qquad \boxed{t=\cfrac{140}{r}}
\\\\\\
\textit{now, when \underline{r} = 45, what is \underline{t}?}\qquad t=\cfrac{140}{45}
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a_n=a_{n-1}+d

where d is the common difference between terms. You can solve for a_n in terms of any of the previous terms of the sequence:

a_n=a_{n-1}+d\implies~a_n=a_{n-2}+2d\implies~a_n=a_{n-3}+3d\implies\cdots\implies~a_n=a_{n-k}+kd

for some integer 1\le k\le n-1

Continuing in this way, you know that the sequence can be defined explicitly in terms of the first term a_1

a_n=a_1+(n-1)d

Given that the 4th term is a_4=-6 and the 11th term is a_{11}=-34, you have the following system of equations.

\begin{cases}-6=a_1+(4-1)d\\-34=a_1+(11-1)d\end{cases}

Solving this system for the two unknowns yields a_1=6 and d=-4.

So, the sequence is given explicitly by

a_n=6+(n-1)(-4)=-4n+5
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Step-by-step explanation:

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2. C
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Answer:

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Step-by-step explanation

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option 1.1: customer 1 withdraws 2 $20 bills AND customer 2 withdraws 2 $20 bills

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