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sweet [91]
3 years ago
8

Which series of transformations results in the image being congruent to the pre-image?

Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0

Answer:uuuuummmmmmmmmm

Step-by-step explanation:iiiii

Jfjjfjfjfjkjfkfwords

Alex73 [517]3 years ago
5 0
Images of transformation are congruent if they were translated, mirrored/flipped or rotated

1)
(x, y) → (–x, –y) mirrored
(x, y) → (0.8x, 0.8y) scale->not congruent
(x, y) → (x, y + 5)

2)
(x, y) → (x, –y) mirrored
(x, y) → (–x, y) mirrored
(x, y) → (x + 1, y – 1) translation
-> is congruent

3)
(x, y) → (x + 5, y + 5) translation
(x, y) → (x, –y) mirror
(x, y) → (2x, y) scale-> not congruent

4)
(x, y) → (3x, 3y) scale->not congruent
(x, y) → (–x, y)
(x, y) → (x – 4, y)

so the second series of transformations is the only one with a congruent after image
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3 years ago
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How many numbers are equal to the sum of two odd, one digit numbers
Paul [167]
Here is a list of the odd number paired

1+3, 1+5, !+7, and !+9  (there are 4 unique sums - 4, 6,8 and 10)
3+5, 3+7, 3+9  (notice I did not pair 3 with 1 and the the only new sum is 12)
5+7, 5+9  (the only new sum is 14)
7+9  (16 is a new sum)

The sums (no repeats) are 4,6,8,10,12,14 and 16 for a total of seven numbers.
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3 years ago
Which parent function is graphed below
aleksandrvk [35]

Answer:

the answer for this question is c because that is the answer

4 0
3 years ago
Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)
melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

f_x = \dfrac{x^2}{a^7-x^7}

= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}

= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}

since  \Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)

Then, it implies that:

\implies  \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}

\mathbf{=  \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}

7 0
2 years ago
Did I do it right????
den301095 [7]
The answer to number 1 is 3 or 1

The answer to number 2 is 4+x < 6
4 0
2 years ago
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