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Andrei [34K]
2 years ago
9

Solve the system of linear equations below. 6x + 3y = 33 4x + y = 15

Mathematics
2 answers:
artcher [175]2 years ago
5 0

After solving the linear equations below, I’ve come up with the answer x = 2 and y = 7. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

lara [203]2 years ago
5 0

Answer: The solution is,

x = 2, y = 7

Step-by-step explanation:

Given system of equations,

6x + 3y = 33  -------(1)

4x + y = 15 ----------(2),

Equation (1) - 3 × equation (2),

We get,

6x - 12x = 33 - 45

-6x = - 12

⇒ x = 2,

Substituting this value in equation (2),

4(2) + y = 15

8 + y = 15

⇒ y = 7,

Hence, the solution of the given system of equation is,

x = 2, y = 7

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1/2

Step-by-step explanation:

6/12

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In the coming year, a vehicle manufacturer has decided to manufacture 150 vehicles per day. The function v = 150d represents the
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v = 150d

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The rate of change of the function representing the number of vehicles manufactured for the coming year is CONSTANT (150) , and its graph is a STRAIGHT LINE . So, the function is a LINEAR function.

I hope this helps!

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3 years ago
Write an expression to represent the sum of three times the square of a number and -7 . In your expression what is the value of
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3 years ago
Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor
kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) Standard deviation of 23 bags

\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)

= 1 - P(z < 12.57)

Calculation the value from standard normal z table, we have,  

P(x < 5.95) = 1 - 1 = 0

c) P( fill volume of 23 bags is below 6 ounces)  = 0.001

P(x < 6)  = 0.001

P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})

Calculation the value from standard normal z table, we have,  

P( z \leq -3.09) = 0.001

\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0
3 years ago
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