7 cm is the ander i think
They will pay 46.60 a month because 460+100=560 and 560/12=46.6
Answer:
Step-by-step explanation:
We are asked to find the integral:
So, let's apply the vertices given in the question.
![\int\limits^1_0\int\limits_{2x}^{3-x}4xy\:dydx=\int\limits^1_0 2xy^2|_{2x}^{3-x}\:dx=\int\limits^1_0 2x[(3-x)^2-(2x)^2]\:dx=\\\\=\int\limits^1_0 2x(9-6x-3x^2)\:dx=6\int\limits^1_0 (3x-2x^2-x^3)\:dx=\\\\=6(\frac{3}{2}x^2-\frac{2}{3}x^3-\frac{1}{4}x^4)|^1_0=6(\frac{3}{2}-\frac{2}{3}-\frac{1}{4})=\frac{7}{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%5Cint%5Climits_%7B2x%7D%5E%7B3-x%7D4xy%5C%3Adydx%3D%5Cint%5Climits%5E1_0%202xy%5E2%7C_%7B2x%7D%5E%7B3-x%7D%5C%3Adx%3D%5Cint%5Climits%5E1_0%202x%5B%283-x%29%5E2-%282x%29%5E2%5D%5C%3Adx%3D%5C%5C%5C%5C%3D%5Cint%5Climits%5E1_0%202x%289-6x-3x%5E2%29%5C%3Adx%3D6%5Cint%5Climits%5E1_0%20%283x-2x%5E2-x%5E3%29%5C%3Adx%3D%5C%5C%5C%5C%3D6%28%5Cfrac%7B3%7D%7B2%7Dx%5E2-%5Cfrac%7B2%7D%7B3%7Dx%5E3-%5Cfrac%7B1%7D%7B4%7Dx%5E4%29%7C%5E1_0%3D6%28%5Cfrac%7B3%7D%7B2%7D-%5Cfrac%7B2%7D%7B3%7D-%5Cfrac%7B1%7D%7B4%7D%29%3D%5Cfrac%7B7%7D%7B2%7D)
Answer:
To solve for n you need to get it by itself
First you want to distribute your 2 through the (3n+14)
-2n+6n+28=-20 (2*3n+2*14= 6n+28)
Now you want to combine any like terms if possible
4n+28=-20 (-2n+6n=4n, both like terms)
Then you want to subtract -28 from both sides
4n=-48 (28-28=0, -20-28=-48)
Lastly you want to divide both sides by 4
n=-12 (4n/4=n, -48/4= -12)
I think 24 if it’s not right then my apologies, hope it helps atleast :)
