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3 years ago

The features of Mercury are named in honor of famous people in which fields of endeavor?

Physics

1 answer:

frozen [14]3 years ago

4 0

Answer:

Writing, Poetry, Philosophy, Painter, Lutheran pastor, Screenwriting, Music, Photography

Explanation:

The International Astronomical Union (IAU) approved the naming of 9 craters to honor artists of various fields. They are:

Alver: Betty Alver was an Estonian writer.

Donelaitis: Kristijonas Donelaitis was a Lutheran pastor

Flaiano: Ennio Flaiano was an Italian screenwriter, playwright, novelist, journalist, and drama critic.

Hurley: James Francis “Frank” Hurley was an Australian photographer and adventurer.

L’Engle: Madeleine L’Engle was an American writer

Lovecraft: Howard Phillips Lovecraft was an American author.

Petofi: Sándor Petőfi was a Hungarian poet.

Pahinui: Charles Phillip Kahahawai “Gabby” Pahinui was a Hawaiian guitar player.

Roerich: Nicholas Roerich was a Russian painter and philosopher.

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Recall that:

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3 years ago

gayle cooks a roast in her microwave oven. the klystron tube in the oven emits photons whose energy is 1.20 x 10^-3 ev. what are

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Answer:

$\lambda=1.03\times 10^{-3}\ m$

Explanation:

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$E=\dfrac{hc}{\lambda}\\\\\lambda=\dfrac{hc}{E}$

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3 years ago

A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the

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Answer:

The maximum length during the motion is $L_{max} = 1.45m$

Explanation:

From the question we are told that

The mass is $m =0.5 kg$

The vertical spring length is $L = 1.10m$

The unstretched length is $L_{un} = 1.30m$

The initial speed is $v_i = 1.3m/s$

The new length of the spring $L_{new} = 1.30 m$

The spring constant k is mathematically represented as

$k = -\frac{F}{y}$

Where F is the force applied $= m * g = 0.5 * 9.8=4.9N$

y is the difference in weight which is $=1.10-0.50=0.6m$

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

Now substituting values accordingly

$k = \frac{4.9}{0.6}$

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The elastic potential energy is given as $E_{PE} = \frac{1}{2} k D^2$

where D is this the is the displacement

Since Energy is conserved the total elastic potential energy would be

$E_T = initial \ elastic\ potential \ energy + kinetic \ energy$

$E_T = \frac{1}{2} k D_{max}^2 = \frac{1}{2} k D^2 + \frac{1}{2} mv^2$

Substituting value accordingly

$\frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2$

$4.085 * D_{max}^2 = 3.69$

$D^2_{max} = 0.9033$

$D_{max} = 0.950m$

So to obtain total length we would add the unstretched length

So we have

$L_{max} = 0.950 + 0.5 = 1.45m$

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