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3 years ago

In a series circuit, the current is _______

Physics

2 answers:

Scrat [10]3 years ago

6 0

Answer:

The option that completes the sentence is;

Equal

Explanation:

A series circuit is a circuit arrangement whereby the components of the circuit are connected in a single chain by joining them end to end, thereby the current flows round the circuit through the singular path of the interconnected component in the circuit and therefore, the current which flows through each component as it flows round circuit, is equal at all points in the circuit.

Therefore, we have that in a series circuit, the current is <u>equal</u> at every point around the circuit.

pishuonlain [190]3 years ago

3 0

<h2>Question:</h2>

In a series circuit, the current is _______

at every point around the circuit. Which of the following completes the sentence?

<h2>Answer:</h2>

In a series circuit, the current is <u>equal</u><u> </u> at every point around the circuit.

<h2><u>#CARRYONLEARNING</u><u> </u></h2><h2><u>#STUDYWELL</u><u> </u></h2>

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Tpy6a [65]

Answer:

The wavelength of the light decreases as it enters into the medium with the greater optical density.

The frequency of the light remains constant as it transitions between materials.

Explanation:

- When a ray of light crosses a boundary between two different materials, it undergoes refraction: the ray changes direction, and it also changes speed, according to the relationship:

$v=\frac{c}{n}$

where v is the speed of the ray of light in the material, c is the speed of light in a vacuum, n is the index of refraction of the material, which is larger for a medium with larger optical density. So, from the equation, we see that the larger the optical density, the smaller the speed of the wave.

- The frequency of the light does not depend on the properties of the medium, so it remains unchanged: therefore the statement

The frequency of the light remains constant as it transitions between materials.

is correct.

- Moreover, the wavelength of the ray of light is related to the speed and the frequency by the equation

$\lambda=\frac{v}{f}$

where v is the speed and f the frequency. Since we have seen that v decreases and f remains constant, this means that the wavelength decreases as well, so the statement

The wavelength of the light decreases as it enters into the medium with the greater optical density.

is also correct.

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