The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.
<h3>Acceleration of the box</h3>
The acceleration of the box is calculated as follows;
vf² = vi² + 2as
a = (vf² - vi²)/2s
a = (11.5² - 13²) / (2 x 8.5)
a = -2.16 m/s²
<h3>Time of motion of the box</h3>
The time taken for the box to travel is calculated as follows;
a = (vf - vi)/t
t = (vf - vi) / a
t = (11.5 - 13) / (-2.16)
t = 0.69 s
<h3>Average power supplied by the friction</h3>
P = Fv
P = (ma)(vf - vi)
P = (1 x -2.16) x (11.5 - 13)
P = 3.24 W
Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.
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Answer:
The value is 
Explanation:
From the question we are told that
The width of the slit is 
The distance of the screen from the slit is D = 1.25 m
The width of the central maximum is 
Generally the width of the central maximum is mathematically represented as

Here m is the order of the fringe and given that we are considering the central maximum, the order will be m = 1 because the with of the central maximum separate's the and first maxima
So

=> 
=> 
=> 
Answer: The chemical energy of reactants is greater than the chemical energy of products.
Explanation: In the given reaction

It can be seen that the energy has been released. Thus we can say that reactants have converted to products by release of energy. Thus energy of products is less as compared to energy of reactants as some of the energy has been released.