This question is not complete.
The complete question is as follows:
One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?
Explanation:
a. Using the expression;
T = 2π√R/g
where R = radius of the space = diameter/2
R = 800/2 = 400m
g= acceleration due to gravity = 9.8m/s^2
1/T = number of revolutions per second
T = 2π√R/g
T = 2 x 3.14 x √400/9.8
T = 6.28 x 6.39 = 40.13
1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute
Answer i dont even know im just putting this cus id ont care
Explanation:
Answer:
<h2>The answer is 5 s</h2>
Explanation:
The time taken can be found by using the formula
d is the distance
v is the velocity
From the question we have
We have the final answer as
<h3>5 s</h3>
Hope this helps you
Answer:
acidic
Explanation:
because the lower you go on the scale the more acidic it is and the closer to the middle the more neutral it is
