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lianna [129]
3 years ago
10

A customer orders 8 bags of rice that each weigh 1/2 kg, and 12 packets of popcorn that each weigh 150 g. What is the total mass

of the order?​
Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0
Rice: .5(8) = 4kg (4000 g)
Popcorn: 150(12) = 1800 g

Total mass = mass of rice (4000 g) + mass of popcorn (1800g)

So...

Total mass = 5,800 g (or 5.8 kg)
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the Following table shows alexandra's investment options over the course of three years. Her initial investment was $1,000 . wri
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The pattern in the given series of amount in the account are in the form of

arithmetic and geometric progression.

  • The function for Option 1 is;  \underline{ f(n) = 1,100 + (n - 1) \cdot 100}
  • The function for Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Reasons:

The given table of values is presented as follows;

\begin{tabular}{c|c|c|c|}Number of years&1&2&3\\Option 1 (Amount in dollars)&1,100&1,200&1,300\\Option 2 (Amount in dollars)&1,100&1,210&1,331\end{array}\right]

In Option 1, the amount in dollars for each year has a common difference of d = 100

The first term, a = 1,100

Therefore;

The Option 1 can be represented as an arithmetic progression , A.P. in the

form, tₙ = a + (n - 1)·d as follows;

For the Option 1, we have;

  • The amount in dollars after <em>n</em> years, \underline{ f(n) = 1,100 + (n - 1) \cdot 100}

For Option 2, it is possible to find;

1,331 ÷ 1,210 = 1,210 ÷ 1,100 = 1.1

Therefore;

The terms in the Option 2 have a common ratio of r = 1.1

The Option 2 is a geometric progression, G.P.

The first term in Option 2 is a = 1,100

Which gives, the nth term, tₙ = a·r⁽ⁿ ⁻ ¹⁾

Therefor;

  • The function for the Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Learn more about arithmetic and geometric progression here:

brainly.com/question/8932895

brainly.com/question/22977503

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