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mixer [17]
3 years ago
5

Classifying Parallelograms-

Mathematics
2 answers:
Afina-wow [57]3 years ago
7 0
1. False
2. False
3. True
4. False 
Hope this helped
erastova [34]3 years ago
6 0
1.False
2.False
3.True
4.False
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Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

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\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

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