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cricket20 [7]
3 years ago
13

A 5-digit code is given to all cashiers at a store to let them log onto the cash register. What is the probability that an emplo

yee receives a code with all 5 numbers the same?
Mathematics
1 answer:
EleoNora [17]3 years ago
3 0

Answer:

The probability that an employee receives a code with all 5 numbers the same is \frac{1}{10^4}.

Step-by-step explanation:

Consider the provided information.

The numbers which we can use in code is: 0,1,2,3,4,5,6,7,8,9

That means there are 10 numbers which we can use.

The total ways of selecting a 5 digit number with all 5 numbers the same = 10.

The total ways of selecting a 5 digit number is: 10×10×10×10×10=10^5

The required probability is:

Probability=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}

Probability=\frac{10}{10^5}

Probability=\frac{1}{10^4}

Hence, the probability that an employee receives a code with all 5 numbers the same is \frac{1}{10^4}.

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A school system is reducing the amount of dumpster loads of trash removed each week. In week 5, there were 40 dumpster loads of
salantis [7]

Answer: c

Step-by-step explanation:

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3 years ago
Nina worked 24 hours and was paid $12.00 an hour. How much was Nina's GROSS PAY
Vitek1552 [10]
Nina’s gross pay is $288;
$12 x 24 = $288
6 0
3 years ago
Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?
malfutka [58]
\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}

Hence, the correct options that apply are options A, D, E and F

7 0
1 year ago
After being rearranged and simplified, which two of the following equations could be solved using the quadratic formula? A) 5x^3
madreJ [45]

Answer:

B & D

Step-by-step explanation:

The quadratic formula can be used to solve for x for any quadratic. Recall a quadratic is any function whose highest exponent known as degree is 2. Looking at the answer selections, A has one term with exponent 3. This isn't possible in the formula. Looking at answer C, the term with exponent 2 has the same coefficient on each side of the equal sign. When it is rearranged these will cancel out no exponent of 2 will be in the equation anymore. Only B & D work after being rearranged and simplified

4 0
3 years ago
7. In how many ways can the same 5-question True / False quiz be
goldenfox [79]

Answer:

243 ways

Step-by-step explanation:

Calculating the number of posible outcomes:

We have n trials.

Each trial has m possible outcomes.

The total number of outcomes is:

T = m^{n}

In this question:

5 questions, that is, 5 trials, so n = 5

Each question has 3 options(True, false or unanswered). So m = 3

How many ways?

T = 3^{5} = 243

3 0
3 years ago
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