Answer:
1. IQ range
2. Frequency
3. Mean
4. Standard deviation and variance
Step-by-step explanation:
To use statistics the researcher must determine the standard deviation, mean and variance. He will need the following to calculate the mean:
1. The IQ score range and the frequency of the range.
To calculate the standard deviation and mean:
1. Need the mean and frequency of the IQ scores
Therefore the 4 things needed is:
1. IQ range
2. Frequency
3. Mean
4. Standard deviation and variance
(x, y)
y = -5x - 1
a. (9, -2) → x = 9, y = -2
-2 = -5(9) - 1
-2 = -46 FALSE
b. (5, 24) → x = 5, y = 24
24 = -5(5) - 1
24 = -26 FALSE
c. (-1, 6) → x = -1, y = 6
6 = -5(-1) - 1
6 = 4 FALSE
d. (-4, 19) → x = -4, y = 19
19 = -5(-4) - 1
19 = 19 TRUE
<h3>Answer: d. (-4, 19)</h3>
The answer is "141.17647058823529411764705882353", hope this helps! Please Mark me the brainliest! ☺
Isolate the variable by dividing each side by factors that don't contain the variable.
x=5
Answer:
B) 8 cm
Step-by-step explanation:
Hello, I can help you with this
according to the question
The length of a rectangle is 3 cm greater than the width of the rectangle.
convert this into algebraic terms
Step 1
do the eqution
Let
W,width
L,Length
The length of a rectangle(L) is(=) 3 cm greater than the width (W+3) of the rectangle.
note:3 cm greater than the width (W+3) means that you need add 3 to the width to obtain the length
L=W+3 equation(1)
the area of the rectangle is 40 square cm
Let
A,Area
Area= 40 cm
A=40
also,A=L*W
40=L*W equation(2)
Step 2
solve the equations
L=W+3 equation(1)
40=L*W equation(2)
replace the value of L from equaiton (1) into equation (2)

we are looking for a distance, so we need the positive valur only.

Step 3
Now, replace the value of W into equation (1) to obtain the length
L=W+3 equation(1)
L=5+3
L=8
so, the length is 8 cm, B) 8 cm
Have a nice day.