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lbvjy [14]
3 years ago
12

Differentiate f(x)= square root of x times sin x

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
Here is the answer of the given mathematical problem above:
In order to differentiate f(x)= square root of x times sin x, you do this.
Use the product rule so that f′(x)=f(x)g′(x)+f′(x)g(x) when f(x)=x√ and<span>g(x)=sin(x)
</span>Next, solve for the derivative of sqrt(x) and sinx first and then plug into the equation for the product rule.
The result would be <span>the derivative of sqrt(x) is 1/2x^-1/2 and </span><span>derivative of sinx is cosx.</span>
zysi [14]3 years ago
3 0
Hello,

y= \sqrt{ x*sin(x) } \\&#10;&#10;y'= \dfrac{sin(x)+x*cos(x)}{2 \sqrt{x*sin(x)} }
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Answer:

Please see attached image and all steps below for both parts

Step-by-step explanation:

Task 1

The following system of equations includes a linear equation and a quadratic one:

\left \{ {{y=x+2} \atop {y=x^2-8x+2}} \right} \}

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

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and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]

There are two solutions: x = 0 and x = 9.

When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.

Task 2

Part 1:

Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10

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Part 2:

let's choose a=9 and b=10 so we use:

9^3+10^3=(9 + 10)\,(9^2-(9)\,(10)+10^2)=(19)\,(81-(90)+100)=19\,(81-180+100)=19\,*\,91=1729

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Lelu [443]
What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other

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Thus it is 1:1.</span>
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