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lbvjy [14]
3 years ago
12

Differentiate f(x)= square root of x times sin x

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
Here is the answer of the given mathematical problem above:
In order to differentiate f(x)= square root of x times sin x, you do this.
Use the product rule so that f′(x)=f(x)g′(x)+f′(x)g(x) when f(x)=x√ and<span>g(x)=sin(x)
</span>Next, solve for the derivative of sqrt(x) and sinx first and then plug into the equation for the product rule.
The result would be <span>the derivative of sqrt(x) is 1/2x^-1/2 and </span><span>derivative of sinx is cosx.</span>
zysi [14]3 years ago
3 0
Hello,

y= \sqrt{ x*sin(x) } \\&#10;&#10;y'= \dfrac{sin(x)+x*cos(x)}{2 \sqrt{x*sin(x)} }
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Y = -3
-3 + 3 = 0
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3 years ago
The third term of the sequence is 120. The fifth term is 76.8 The explicit rule for the geometric sequence is an=?(?)n-1
gulaghasi [49]

Answer:

The explicit rule of the geometric sequence

 aₙ   = 187.5 (0.8)ⁿ⁻¹

Step-by-step explanation:

<u><em> Step(i):-</em></u>

Given that the third term of the sequence = 120

        tₙ = a rⁿ⁻¹  

       t₃  = a r³⁻¹ = ar²

        120 = ar² ..(i)

Given that the fifth term of the given geometric sequence = 76.8

        tₙ = a rⁿ⁻¹  

       t₅  = a r⁵⁻¹ = a r⁴

   76.8  = a r⁴...(ii)

<u><em>Step(ii):</em></u>-

 Dividing (ii) and (i)

         \frac{ar^{4} }{ar^{2} } = \frac{76.8}{120}

        r²   = 0.64

       r    =√ 0.64 = 0.8

Substitute r= 0.8 in equation (i)

         120 = ar²

       120 = a(0.8)²

⇒      a = \frac{120}{0.64} =187.5

<u><em>Step(iii):-</em></u>

The explicit rule of the geometric sequence

                 aₙ  = a rⁿ⁻¹

put a= 187.5  and r = 0.8

                aₙ   = 187.5 (0.8)ⁿ⁻¹

 

7 0
3 years ago
I need help with this question it is on mathswatch btw.
navik [9.2K]

Answer:

x is less then or equal to -3

x<-3 (the < has to have a line underneath)

Step-by-step explanation:

4 0
2 years ago
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
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shusha [124]

Answer:

49.0809

Step-by-step explanation:

Round it up to 49.10

8 0
3 years ago
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