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Aliun [14]
3 years ago
6

Please help my geometry assginment, brainly if answer properly

Mathematics
1 answer:
QveST [7]3 years ago
5 0

Answer:

Please mark me brainliest     :)   Hope it helps

Step-by-step explanation:

So basically, since CD and AB are parallel, that means that angle2 and angle3 are similar, due to the corresponding angle postulate. Furthermore, it is given that AG and CE are similar, so angle1 and angle2 are similar on the same principle.

This means that angle3 and angle4 are similar, since it is given that angle1 and angle4 are similar. A bisecting line divides a whole angle into two, equal value angles, and since ECF is composed of angle3 and angle4, and angle3 and angle4 are the same value, that means the line that forms angle3 and angle4 is bisecting the ECF, therefore CD bisects ECF.

You might be interested in
JL = 28,<br> KL= 5x + 6, and<br> JK = 3x + 6,
Alexeev081 [22]

Answer:

KL = 16

Step-by-step explanation:

For this problem, JL is the sum of KL and JK.  So we can say this:

JK + KL = JL

( 3x + 6 ) + ( 5x + 6 ) = 28

8x + 12 = 28

8x = 16

x = 2

So, now we can find KL:

5x + 6 = ?

5(2) + 6 = ?

10 + 6 = ?

16 = ?

So the length of KL is 16.

Cheers.

7 0
3 years ago
5. Find the value of x in each of the following.<br> 2/3=6/x. 4/7=x/21
nikitadnepr [17]
6/9 and 12/21
i think this is the answer your looking for
7 0
2 years ago
Solve the inequality.
xenn [34]

Answer:

x < -24(option

Step-by-step explanation:

-¼x - 12 > -6

Add 12 to both sides

-¼x - 12+12 > -6+12

-¼x > 6

Divide both sides by -¼

x < 6 ÷ -¼

Please note that the inequality sign changes when divided by negative (minus). This is a rule in inequalities.

x < 6 × -4

x < -24

I hope this was helpful, please mark as brainliest

8 0
3 years ago
PLEASE HELP MEE
wel

Hey!

Sorry this answer is too late to help you but hopefully it will help future users...

an= 1/4 * an-1

a1= -64

What is in bold is what you type into the answer box.

I also have a pic attached.

I hope this helps you! Good luck on the test!

4 0
3 years ago
Read 2 more answers
The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d
KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                     = \sqrt{(1-4)^2+(-5+3)^2}

                     = \sqrt{(-3)^2+(-2)^2}

                     = \sqrt{13}

Distance BC = \sqrt{(4-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance CD = \sqrt{(-2-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance AD = \sqrt{(1+2)^2+(-5+3)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Slope of AB (m_{1}) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                           = \frac{4-1}{-3+5}

                           = \frac{3}{2}

Slope of BC (m_{2}) = \frac{4-1}{-3+1}

                            = -\frac{3}{2}

If AB and BC are perpendicular then,

m_{1}\times m_{2}=-1

But it's not true.

[m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2}) = -\frac{9}{4}]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = \frac{4+2}{-3+3}

                                    = Not defined (parallel to y-axis)

Slope of diagonal AC = \frac{1-1}{-1+5}

                                    = 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0
3 years ago
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