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True [87]
2 years ago
13

Help me asap

Mathematics
2 answers:
ankoles [38]2 years ago
4 0

Answer:

1/5 + 2/5 = 3/5

Step-by-step explanation:

your welcome

Paul [167]2 years ago
4 0

Answer:

1/5+z=3/5

Step-by-step explanation:

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Which of the following is a radical equation?<br> Ox√3=13<br> O x+√3=13<br> O√x+3=13<br> O x+3=√13
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What is 9.08÷9 show work
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4 0
3 years ago
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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
3 years ago
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