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3 years ago

Triangle E G F is shown. The length of E G is 10 and the length of E F is 12. Angle E F G is 56 degrees.

Mathematics

1 answer:

omeli [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Triangle E G F is shown. The length of E G is 10 and the length of E F is 12. Angle E F G is 56 degrees.

Trigonometric area formula: Area = One-half a b sine (C)

The area of triangle EFG is 34.8 square units. What is the perimeter of triangle EFG to the nearest unit?

29 units

30 units

41 units

60 units

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Which is greater than 4?<br><br>(a) 5,<br>(b) -5,<br>(c) -1/2,<br>(d) -25.

Archy [21]

Answer: a). 5

Explanation:
5 > 4

5 0

3 years ago

0. Completa:<br>4.520.389 = 4__ +5CM + __+__+__+__+__<br>

stira [4]

Answer:

Step-by-step explanation:

In this proble, we defined:

D represents tens.
C represents hundreds.
M represents millions.
U is units.

So, the given number is 4,520,389, where we need to state the proper variable according to the position of each digit and its value.

4,520,389 = 4M + 5CM + 2DM + 3C + 8D + 9U

In words, the first term represents 4 millions, the second term represents 5 hundred thousands, the third term represents twenty thousands, the fourth term represents three hundreds, the fifth term represents eighty and the las term represents 9 units.

4 0

3 years ago

HALP PLEASE NEED HALP, ASAP??

andre [41]

Answer:

Step-by-step explanation:

since -4 *-2 = 8 and -8+8=0

0*-2=0

0+5=5

7 0

3 years ago

If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

$\sin 2A = 2\cdot \sin A\cdot \cos A$ (4)

$\csc 2A = \frac{1}{\sin 2A}$ (5)

$f(A) = \sin 2A + \csc 2A$

$f(A) = \sin 2A + \frac{1}{\sin 2A}$

$f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}$

$f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}$

If we know that $\sin A \approx 0.382$ and $\cos A \approx 0.924$ , then the value of the function is:

$f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}$

$f(A) = 2.122$

8 0

3 years ago

7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con

sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let $p_{1}$ be the probability that commercial cars have rear license plates and $p_{2}$ be the probability that connected trucks have rear license plates.

Cars Trucks Total

Total 2049 334 2383

x 239 45 284

p 0.1166 0.1347 0.1191

α=0.05

Hypothesis will be :

$H_{0}:p_{1} =p_{2}$

$H_{1} :p_{1} < p_{2}$

It is a left tailed test at 0.05 significance.

Standard errors of p= $\sqrt{p(1-p)/n}$

= $\sqrt{(0.1191*0.8809)/2383}$

= $\sqrt{0.1049/2383}$

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0

2 years ago