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olchik [2.2K]
3 years ago
6

The cost of 4 pounds of grapes is $24.36.wgat is the constant of proportionality

Mathematics
1 answer:
IRINA_888 [86]3 years ago
6 0
The answer
A:6.09

Th explanation
Divide 24.36 by 4 and that’s what you get
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Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x?
vovikov84 [41]

Answer:

x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}

Therefore, Option 1 is correct.

Step-by-step explanation:

We have been given the quadratic equation:

5x^2+3x-4=0

If we compare it will general quadratic equation which is: ax^2+bx+c=0

Here, a=5,b=3 and c= -4.

Now, we will use the formula:

And then x=\frac{-b\pm\sqrt{D}}{2a}

Where,D=b^2-4ac

x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}

Therefore, Option 1 is correct.

6 0
3 years ago
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A highschool football team had a win to loss ratio of 4:1. If they played 15 games in that season, how many games did they win?
Colt1911 [192]
13 because when you have 15 games and you win 13, you have 2 that you lost
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3 years ago
Ula for a Variable
Elodia [21]

Answer: 80 votes

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8 0
3 years ago
What is the solution to the equation 3 x+ 2 = -x-57<br> X=-8<br> o x=-7<br> o x=7<br> O X=8
luda_lava [24]

Answer:

x = -59/4

Step-by-step explanation:

3 x+ 2 = -x-57

Add x to each side

3 x+x+ 2 = -x+x-57

4x+2 = -57

Subtract 2 from each side

4x +2-2 = -57-2

4x = -59

Divide each side by 4

4x/4 = -59/4

x = -59/4

4 0
3 years ago
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Jerry was using matrices to solve the system of three equations. He has shown all his steps. Did he make a mistake if so in what
melomori [17]

There are several ways to solve a system of equation; one of these ways is the use of matrix.

<em>Jerry made a mistake at step 2</em>

From the attachment, the step 1 is represented as:

\mathbf{\frac 12R_1 \left[\begin{array}{cccc}1&1&1&0\\5&3&-2&-4\\3&2&1&1\end{array}\right] }

The equation in step 2 is given as:

\mathbf{R_2 = 5R_1 - R_2}

This means that:

We subtract the elements of row 2 from the elements of row 1, multiplied by 5

So, we have:

\mathbf{R_2 = 5\left[\begin{array}{cccc}1&1&1&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

Expand

\mathbf{R_2 = \left[\begin{array}{cccc}5&5&5&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

Subtract corresponding cells

\mathbf{R_2 = \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

So, the new row 2 elements should be:

\mathbf{ \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

However, the row 2 elements of Jerry's steps are:

\mathbf{R_2 = \left[\begin{array}{cccc}0&-2&-7&-4\end{array}\right] }

This means that:

Jerry made a mistake; and the mistake is at step 2

Read more about matrix at:

brainly.com/question/21848291

4 0
2 years ago
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