Answer: 3, 4
Step-by-step explanation:
and the common factor between these 2 numbers is 1 so 3,4 is its greatest factor
![1\frac23-\frac34](https://tex.z-dn.net/?f=1%5Cfrac23-%5Cfrac34)
Write 1 2/3 as an improper fraction...
1 = 3/3. Plus the 2/3 makes 5/3.
![\frac53-\frac34](https://tex.z-dn.net/?f=%5Cfrac53-%5Cfrac34)
To add/subtract fractions, they need the same denominator. (bottom number)
We can change the denominator by multiplying the top and bottom of a fraction by the same number. (it will stay equal, like 1/2 and 2/4)
Let's change 5/3 and 3/4 to a denominator of 12.
5/3 = 20/12 (bottom multiplies by 4, so does the top)
3/4 = 9/12 (bottom multiplies by 3, so does the top)
![\frac{20}{12}-\frac9{12}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B12%7D-%5Cfrac9%7B12%7D)
Now we just subtract the 20 minus 9 twelfths. (the twelfths act as a sort of unit)
Answer:
2/3pix³ or ![\frac{2}{3} \pi x^3\\](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%5Cpi%20x%5E3%5C%5C)
Step-by-step explanation:
This problem brothers on the mensuration of solid shapes, a cone.
we know that the expression for the volume of a cone is
![volume= \frac{1}{3} \pi r^2h](https://tex.z-dn.net/?f=volume%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2h)
let the radius r of the cone be= ![x](https://tex.z-dn.net/?f=x)
and the height h is =![2x](https://tex.z-dn.net/?f=2x)
we can now solve the expression that represents the volume of the cone, in cubic units.
![volume= \frac{1}{3} \pi *x*2x\\\volume= \frac{1}{3} \pi *2x^3\\\volume= \frac{2}{3} \pi x^3\\](https://tex.z-dn.net/?f=volume%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20%2Ax%2A2x%5C%5C%5Cvolume%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20%2A2x%5E3%5C%5C%5Cvolume%3D%20%5Cfrac%7B2%7D%7B3%7D%20%5Cpi%20x%5E3%5C%5C)
Answer:
Angle E is 30⁰
Explanation:
If triangle ABC= triangle DFE then they are both the same it's just that in this case the triangles are mirrored meaning that Angle C= Angle E
Making Angle E: 30⁰
Since she donates 25%, take 25% and multiply it by 1,200
![.25 * 1,200 = 300](https://tex.z-dn.net/?f=.25%20%2A%201%2C200%20%3D%20300)
or,
![\frac{1}{4} * 1,200 = 300](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%2A%201%2C200%20%3D%20300)