Answer:
Explanation:
The table that shows the pattern for this question is:
Time (year) Population
0 40
1 62
2 96
3 149
4 231
A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.
Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.
Thus you must find both P₀ and r.
<u>1) P₀ </u>
Using the first term of the sequence (0, 40) you get:
P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀
Then, P₀ = 40
<u> 2) r</u>
Take two consecutive terms of the sequence:
- P(1) / P(0) = 40r / 40 = 62/40
You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55
<u>3) Model</u>
Thus, your model is P(x) = 40(1.55)ˣ
<u> 4) Population of moose after 12 years</u>
- P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.
If you expand this equation first
You get -4u+6+3u=3u+24
And if you simplify that you get:
-u+6=3u+24
Now you need to solve this equation to find u
First bring 3u to the other side to -u-3u (the positive changes to negative)
Now the equation is
-4u+6= 24
Take 6 of both sides
-4u=24-6= 18
-4u= 18
So u= -18/4
Which simplifies to -9/2
Answer: -9/2
the answer is 21/77 because you multiplied 11 by 7 to get 77, you multiply 7 by which gives you 21/77
Answer:
My answers were (1,1) for both lmk if it works ;)
Step-by-step explanation:
Answer:
1 in 47.
Step-by-step explanation:
Add all of the outcomes (28 + 2 + 3 + 14).
You'll get 47.
Do not add the 1s.
There is your answer.
1 in 47.
