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Margarita [4]
2 years ago
12

Calculate the mass of a rectangular solid that has a density of 2.53 g/cm3 and which measures 25 mm by 1.80 cm by 3.00 cm.

Mathematics
1 answer:
Annette [7]2 years ago
3 0
Mass = density x volume 
1st we need to get the volume 
V = (25*10^-1) * (1.8) * (3) 
V = 13.5 cm3 
mass = 2.53 * 13.5 
mass = 34.155 kg 
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topjm [15]
It’s D


the reason why is because the multiplier must be between 1 and 10
(
1
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so first more your decimal there which you get:
2.34
then just count how many numbers the decimal jumped, if the decimal moved left the exponent is positive and if it moved right, as in your number, the exponent is negative

yours moved 3
6 0
1 year ago
How many terms are there in a geometric series if the first term is 4, the common ration is 3 and the sum of the series is 160
Marina CMI [18]
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=3\\
S_n=160
\end{cases}

\bf 160=4\left( \cfrac{1-3^n}{1-3} \right)\implies 160=4\left( \cfrac{1-3^n}{-2} \right)\implies 160=-2(1-3^n)
\\\\\\
160=2(3^n-1)\implies \cfrac{160}{2}=3^n-1\implies 80=3^n-1
\\\\\\
81=3^n~~
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^4=3^n\implies 4=n
3 0
2 years ago
what is the value of the X variable in the solution to the following system of equations for 4x+ 2y =6 x-y=3
blagie [28]
X=1,y=1

1 )4x+2y=6
2 ) x -y=3

2(x2) ) 2x - 2y=6
6 0
3 years ago
Read 2 more answers
In a survey of 150 students at Kennedy Middle School, 48% said
BigorU [14]

Answer:

660 people

Step-by-step explanation:

48% people prefer thick pizza

1 375 people x 48% = 660

6 0
2 years ago
Please help! Brainliest to correct.
Margarita [4]

Answer:

We are given the following in the question:

where P(x) in millions is the number of U.S. travelers from 1990 through 2009 and x = 1 represents 1991.

We have to approximate the number of U.S. travelers to other countries in each given year.

​(a) 1990

We put x = 0 in the given function.

Thus, there are 48.09 millions U.S. travelers in 1990.

​(b) 2000

We put x = 10 in the given function.

Thus, there are 56.888 millions U.S. travelers in 2000.

​(c) 2009

We put x = 19 in the given function.

Thus, there are 31.085 millions U.S. travelers in 2009.

Step-by-step explanation:

Hope this helps:) plz mark as brainliest I really need it:)

7 0
2 years ago
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